An airplane propeller starts from rest and 2 seconds later it is rotating with an angular...

An airplane propeller starts from rest and 2 seconds later it is rotating with an angular speed of 350 rev/min. If the angular acceleration is constant, calculate

(a) its angular acceleration.

(b)how many revolutions did the propeller undergo during this time?

Solutions

Expert Solution

1 revolution = 2 radians

1 minute = 60 seconds

Initial angular speed of the propeller = ₁ = 0 rad/s (Starts from rest)

Angular speed of the propeller after 2 sec = ₂ = 350 rev/min = 350 x (2/60) rad/s = 36.652 rad/s

Time period = T = 2 sec

Angular acceleration of the propeller =

₂ = ₁ + T

36.652 = 0 + (2)

= 18.326 rad/s²

Angle through which the propeller rotates in these 2 sec =

= ₁T + T²/2

= (0)(2) + (18.326)(2)²/2

= 36.652 rad

Number of revolutions made by the propeller in 2 sec = n

n = 5.833 rev

a) Angular acceleration of the propeller = 18.326 rad/s²

b) Number of revolutions made by the propeller in 2 sec = 5.833 rev

genius_generous answered 1 week ago

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