Question

1. Use NumPy to create a My_Array; a 3 by 3 array where i_n,m = n + m. (e.g., the first row first column would be 0+0=0, second row first column would be 1+0=1, etc). complete the following using NumPy:
   1. Compute the mean, median, range, and variance of this array
   2. Find the inverse or pseudo inverse
   3. Find the determinant
2. Perform the following operations on My_Array
   1. Create My_1D_Array by reshaping My_Array into a 1-dimensional array
   2. Create a new array that is the transpose of My_1D_Array
   3. Add this new array to My_1D_Array, what is the result? Why is this the result we see?

Answer 1

Adding the transpose and the original matrix will result in the original matrix*2.

All the functions are built into the numpy library.

CODE :

import numpy as np

My_arr = np.fromfunction(lambda m, n: m + n, (3, 3), dtype=int)

mean = np.mean(My_arr)
median = np.median(My_arr)
r = np.ptp(My_arr)
variance = np.var(My_arr)
print("Mean : ",mean," Median : ",median," Range : ",r," Variance : ",variance)

pinv = np.linalg.pinv(My_arr)
print("Pseudo-Inverse :\n ",pinv)

det = np.linalg.det(My_arr)
print("Determinant : ",det)

a1 = My_arr.flatten()
a2 = My_arr.transpose()
a3 = My_arr+a2

print("Flattened array : ",a1,"\nTranspose : \n",a2,"\n Transpose + My_arr :\n",a3)