In: Statistics and Probability
1) a) H0: P = 0.72
H1: P < 0.72
b) = 30/45 = 0.67
The test statistic z = (- P)/sqrt(P(1 - P)/n)
= (0.67 - 0.72)/sqrt(0.72(1 - 0.72)/45)
= -0.75
P-value = P(Z < -0.75)
= 0.2266
C) At alpha = 0.05, since the p-value is greater than the alpha(0.2266 > 0.05), so we should not reject the null hypothesis.
D) At 5% significance level there is not sufficient evidence to support the claim that the population proportion of women athletes is less than 72%.
2) a) H0: = 25
H1: > 25
B) The test statistic z = ()/()
= (25.7 - 25)/(5.3/)
= 8.17
P-value = P(Z > 8.17)
= 1 - P(Z < 8.17)
= 1 - 1 = 0
C) Since the p-value is less than the significance level (0 < 0.02), so we should reject the null hypothesis.
D) So at 0.02 significance level there is sufficient evidence to support the researcher's claim that the mean weight of one-year old boys is greater than 25 pounds.