6.20. A convenience store owner wants to know how long his customers spend browsing the store...

6.20. A convenience store owner wants to know how long his customers spend browsing the store before making a purchase. It is found that time spent is normally distributed with an average of m = 5 minutes and a standard deviation of s=2 : 2 minutes. Using a random sample of 14 customers, what is the probability that a customer, on average, will spend less than 4 minutes browsing the store?

Solutions

Expert Solution

Solution :

Given that ,

mean = = 5

standard deviation = = 2

n = 14

= = 5 and

= / n = 2/ 14 = 0.5345

P( < 4) = P(( - ) / < (4 - 5) / 0.5345)

= P(z < -1.87)

= 0.0307 Using standard normal table,

The probability that a customer, on average, will spend less than 4 minutes browsing the store is 0.0307.

milcah answered 1 month ago

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