For a position vector d=(-7.1i+-0.1j)m, determine the x-component of the unit vector. For a position vector...

For a position vector d=(-7.1i+-0.1j)m, determine the x-component of the unit vector.

For a position vector d=(-7.1i+-0.1j)m, determine the y-component of the unit vector.

The direction of a 454.7 lb force is defined by the unit vector u₁=cos(30°)i+sin(30°)j. Determine the x-component of the force vector.

Expert Solution

Given,

Position vector, d = [ (-7.1) i + (-0.1) j ] m

The x and y components of unit vector in the same direction as that of given position vector can be determined as follows:

Hence,

x - component of unit vector = - 0.9999 m

y - component of unit vector = - 0.0141 m

Now, in the second part of question,

Given, magnitude of force = 454.7 lb

Unit vector of this force, u1= (cos 30)i + (sin 30)j

Then, the x - component of force vector can be determined as follows:

Hence, the x - component of force vector = 393.78 lb

Ally Wells answered 7 months ago

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