Question

In: Chemistry

At 200 K, the compression factor of oxygen varies with pressure as shown in the table...

At 200 K, the compression factor of oxygen varies with pressure as shown in the table below. Evaluate the fugacity of oxygen at this temperature and 124 atm.

p/atm 1.0000 4.0000 7.0000 10.000 40.00 70.00 100.0
Z 0.9971 0.98769 0.9788 0.9695 0.8734 0.7764 0.6871

Solutions

Expert Solution

Theta = Z – 1/ p ‚ dp   

which is the area under the curve of Z - 1 p vs. p,

where p is the x-value and Z - 1 p is the y-value, in an x, y coordinate system.

The fugacity coefficient f is then the antilog of the area under the curve.

The fugacity of oxygen, in atm = theta p, where p is the pressure in atm.

Make a list of the p and z values given in the problem.

Using the p and z lists, make a list for the Z - 1 p values. Finally, make a list of {p, Z - 1 p } values. Don't forget to transpose.

p = 81.0, 4.0, 7.0, 10.0, 40.0, 70.0, 100.0<;

z = 80.9971, 0.98796, 0.97880, 0.96956, 0.8734, 0.7764, 0.6871<;

yvalue = (z – 1)/ p;

points = [8p, y value]

data = [Transpose[ points]

area =1/2 * sum[ (y value[i+i]) + y value[i]) * ∗(p[][i + 1]] – p[[i]]),{I,1,6]]

The fugacity coefficient φ at 100 atm = 0.73315

−0.310405

Take the anti log of the area to find f:

fugcoeff = Exp[area];

Print["The fugacity coefficient φ at 100 atm = ", fugcoeff]

The fugacity of O2 at 200 K and 100 atm = 73.315 atm.


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