The two half cell reactions can be expressed as follows: Li+1 + e- + C6 à...

The two half cell reactions can be expressed as follows:

Li⁺¹ + e- + C₆ à LiC₆ E_o = -2.84 V

Li⁺¹ + e- + CoO₂ à LiCoO₂ E_o = +0.25 V

A. Which of the two reactions will undergo reduction and which one will undergo oxidation when the battery discharges (spontaneous reaction)?

B.What is the theoretical voltage that can be produced by this cell at standard conditions?

C.Write the complete spontaneous redox reaction that combines the half cell reactions.

Solutions

Expert Solution

Li⁺¹ + e- + C₆ --------------> LiC₆ E_o = -2.84 V oxidation

Li⁺¹ + e- + CoO₂ --------------> LiCoO₂ E_o = +0.25 V reduction

LiC6 ------------------> Li^+ + e^- + C6 E0 = 2.84v oxidation half cell reaction

Li⁺¹ + e- + CoO₂ --------------> LiCoO₂ E_o = +0.25 V reduction half cell reaction

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LiC6 + CoO2 ------ C6 + LiCoO2 E0cell = 3.09v

queen_honey_blossom answered 1 year ago

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