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In: Chemistry

The two half cell reactions can be expressed as follows: Li+1 + e- + C6 à...

The two half cell reactions can be expressed as follows:

Li+1 + e- + C6 à LiC6                           Eo = -2.84 V

Li+1 + e- + CoO2 à LiCoO2           Eo = +0.25 V

A. Which of the two reactions will undergo reduction and which one will undergo oxidation when the battery discharges (spontaneous reaction)?

B.What is the theoretical voltage that can be produced by this cell at standard conditions?

C.Write the complete spontaneous redox reaction that combines the half cell reactions.

Solutions

Expert Solution

A.

Li+1 + e- + C6 --------------> LiC6                           Eo = -2.84 V oxidation

Li+1 + e- + CoO2 --------------> LiCoO2           Eo = +0.25 V reduction

B.

LiC6 ------------------> Li^+ + e^- + C6                E0   = 2.84v oxidation half cell reaction

Li+1 + e- + CoO2 --------------> LiCoO2           Eo = +0.25 V    reduction half cell reaction

----------------------------------------------------------------------------------------------------------------------

LiC6 + CoO2 ------ C6 + LiCoO2                      E0cell   = 3.09v

c.

LiC6 + CoO2 ------ C6 + LiCoO2                      E0cell   = 3.09v

queen_honey_blossom answered 2 years ago
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