Question

Two pucks are sliding across a frictionless surface. Puck A has a mass of .330 kg and a velocity of 5.50 m/s in the x direction. puck be has a mss of .440 kg and a velocity of 6.60 m/s in the negative x direction.

the pucks collide an bounce of each other. after the collision puck a has a velocity of 1.10 m/s in the positive y-direction. What are the x and y components of the velocity of puck ba fter the collision.

Answer 1

mass of puck A = m_a = 0.330 kg

mass of puck B = m_b = 0.440 kg

Along X-direction ::

initial velocity of puck A = V_axi = 5.50 m/s

initial velocity of puck B = V_bxi = - 6.60 m/s

final velocity of Puck A = V_axf = 0 m/s

final velocity of Puck B = V_bxf

Using conservation of momentum along X-direction ::

m_a V_axi + m_b V_bxi = m_a V_axf + m_b V_bxf

(0.330) (5.50) + (0.440) (-6.60) = (0.330) (0) + (0.440) V_bxf

V_bxf = - 2.475 m/s               along negative X-direction

Along Y-direction ::

initial velocity of puck A = V_ayi = 0 m/s

initial velocity of puck B = V_byi = 0 m/s

final velocity of Puck A = V_ayf = 1.10 m/s

final velocity of Puck B = V_byf

Using conservation of momentum along X-direction ::

m_a V_ayi + m_b V_byi = m_a V_ayf + m_b V_byf

(0.330) (0) + (0.440) (0) = (0.330) (1.10) + (0.440) V_byf

V_byf = - 0.825 m/s               along negative Y-direction