Question

You are bringing a spring pendulum (i.e. a mass attached to a spring) and a regular pendulum (think ball on a string) to the International Space Station. Because the ISS is in orbit around the Earth you (and everything else on board) experience apparent weightlessness. Under these conditions, which of the following statements is correct when you displace both pendulums from their respective equilibrium positions (ie try to make them oscillate): Group of answer choices

The spring pendulum will oscillate. The regular pendulum will not oscillate.

Both pendulums will oscillate with twice the frequency they would have in our laboratory on Earth.

Both pendulums will oscillate with the same frequency they would have in our laboratory on Earth.

None of the pendulums will oscillate.

When displaced, it just sits there. The regular pendulum will oscillate. The spring pendulum will not oscillate.

Answer 1

The spring pendulum will osscillate and the regular pendulum will not osscillate.

Here when we bring both the simple pendulum with a spring attached to the mass and thre regular pendulum with the bob is attached to the end of the string to the international space station,where the body feels the wieghtless ness as in the case of the free fall,or the gravitational force at the body in the space station is used for the purpose of providing the centripetal force for executing the circular motion the the respective orbit around the earth.

So,all the bodies placed in the space station feels wieghtlessness or feeling no gravitational force of attraction or the value of the acceleration due to gravity, seems to be zero in the space station as it feels wieghtlessness.

So,we have,

Time period of the regular pendulum,

Here time period T is dependant on both length and the value of

But as the body doen't feels gravitational force in the space station,or feeling wieghtlessness,

So,the time period of the regular pendulum will becomes infinity,or the frequency of the pendulum, will become zero,indicating that the regular pendulum remains at rest or not osscillating.

But fotr the mass-spring pendulum when bringds to the space station,we have time period of the pendulum,

where,m=mass attached to the spring (kg).

K=spring constant of the spring used.

So,here in this pendulum time period only depends on the mass of the block hanged 'm' on the spring and the spring constant of the spring 'k' used in the pendulum,which only depends on the nature of the spring,and is independant on other factors such as the gravitational force or related parameters.

So,even though the space station doesnt feels gravitation or feels wieghtlessness the spring pendulum will begins to osscillate with a finite time period as calculated from the above equation.

Please upvote the answer...