In: Statistics and Probability
4. Suppose that an insurance company charges $1150
per year to cover a car in a nearby city. Suppose that there are
three different scenarios that the company has to consider:
a. There is a .0005 probability that the policy holder
will cause a fatality and the company will pay $1,000,000.
b. There is a .01 probability that the policy holder
will injure someone and the company will pay $20,000.
c. There is a .1 probability that the policy holder
will be in an accident and the company will pay $2,000.
What is the expected value for the policy and is it wise for the
company to continue to offer it?
SOLUTION:
From given data,
( 4.) Suppose that an insurance company charges $1150 per year to cover a car in a nearby city. Suppose that there are three different scenarios that the company has to consider:
a. There is a .0005 probability that the policy
holder will cause a fatality and the company will pay
$1,000,000.
b. There is a .01 probability that the policy holder
will injure someone and the company will pay $20,000.
c. There is a .1 probability that the policy holder
will be in an accident and the company will pay $2,000.
What is the expected value for the policy and is it wise for the company to continue to offer it
Expected value for the company = $1150 - (0.0005 x $1000000) - (0.01 x $20000) - (0.10 x $2000)
= 1150 - 500 - 200 - 200
= $250
Since the expected value for the company is positive, it is wise for the company to continue to offer it.