Question

In: Statistics and Probability

Suppose in an asymmetric and continuous distribution P(X< -131) = P(-131<X< -57) = P(-57 < X<...

Suppose in an asymmetric and continuous distribution P(X< -131) = P(-131<X< -57) = P(-57 < X< 29) = P(X>29). Which of the following is correct?

A. mean=median=-131

B. mean=median= -57

C. median is -131, mean is unknown

D. median is -57, mean is unknown

E. median is -34, mean is unknown



In Questions 2-4 suppose there are a total of 15 Carbon Monoxide Detectors in a building and event “Y” is defined as Y={At least 9 of these detectors work}. Further suppose P(each detector work)=0.8, and detectors are independent of each other. Which of the following is the Ybar (complement of Y)?

A. Ybar={At least 5 detectors fail}

B. Ybar={At least 6 detectors fail}

C. Ybar={At most 6 detectors fail}

D. Ybar={At least 7 detectors fail}

E. Ybar={At most 7 detectors fail}



What is the probability that detectors number 3, 4, 11, 15 fail and the other 11 detectors work?

A. 0.8^4 * 0.2^11 * 15!/(4! * 11!)

B. 0.8^4 * 0.2^11

C. 0.8^11 * 0.2^4 * 15!/(4! * 11!)

D. 0.8^11 * 0.2^4



What is the probability that 11 detectors work and 4 detectors fail? (Hint: Here we don’t care which 4 to fail, just any 4).

A. 0.8^4 * 0.2^11 * 15!/(4! * 11!)

B. 0.8^4 * 0.2^11

C. 0.8^11 * 0.2^4 * 15!/(4! * 11!)

D. 0.8^11 * 0.2^4



Solutions

Expert Solution

ANSWER:

A)

There re  4 square with zones are given so the qualities will compare to 25th, 50th and 75th percentile.

Consequently, 25th percentile = - 131

50th percentile = - 57

75th percentile = 29.

Since this circulation is skewed, we can't enlighten anything regarding mean from the given data.

Middle = 50th is percentile = - 57

Option D is correct answer

B)

Required data is

Total detector =15

Y={at lease 9 detectors work}

P(each detector work)=0.8 =?

Y complement is :

Y bar={At least 7 detectors fail}.

Option D is correct answer .

C)

Required data is given by

Detectors numbers are 3,4,11,15

We have to obtained probability is

P(Detectors 3,4,11,15 fails)= 0.8^11 * 0.2^4.

Option D is correct answer .

D)

Required information is given by

probability 11 detectors is work and 4 detectors are fail than

Here,

Probability is

=P(Any Four detector fails )

=(15 c 4) *(0.8) ^(11 )*(0.2)^(4).

Option is C correct answer .


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