In: Statistics and Probability
Suppose in an asymmetric and continuous distribution P(X< -131) = P(-131<X< -57) = P(-57 < X< 29) = P(X>29). Which of the following is correct? A. mean=median=-131 B. mean=median= -57 C. median is -131, mean is unknown D. median is -57, mean is unknown E. median is -34, mean is unknown
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In Questions 2-4 suppose there are a total of 15 Carbon Monoxide Detectors in a building and event “Y” is defined as Y={At least 9 of these detectors work}. Further suppose P(each detector work)=0.8, and detectors are independent of each other. Which of the following is the Ybar (complement of Y)? A. Ybar={At least 5 detectors fail} B. Ybar={At least 6 detectors fail} C. Ybar={At most 6 detectors fail} D. Ybar={At least 7 detectors fail} E. Ybar={At most 7 detectors fail} |
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What is the probability that detectors number 3, 4, 11, 15 fail and the other 11 detectors work? A. 0.8^4 * 0.2^11 * 15!/(4! * 11!) B. 0.8^4 * 0.2^11 C. 0.8^11 * 0.2^4 * 15!/(4! * 11!) D. 0.8^11 * 0.2^4
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What is the probability that 11 detectors work and 4 detectors fail? (Hint: Here we don’t care which 4 to fail, just any 4). A. 0.8^4 * 0.2^11 * 15!/(4! * 11!) B. 0.8^4 * 0.2^11 C. 0.8^11 * 0.2^4 * 15!/(4! * 11!) D. 0.8^11 * 0.2^4
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ANSWER:
A)
There re 4 square with zones are given so the qualities will compare to 25th, 50th and 75th percentile.
Consequently, 25th percentile = - 131
50th percentile = - 57
75th percentile = 29.
Since this circulation is skewed, we can't enlighten anything regarding mean from the given data.
Middle = 50th is percentile = - 57
Option D is correct answer
B)
Required data is
Total detector =15
Y={at lease 9 detectors work}
P(each detector work)=0.8 =?
Y complement is :
Y bar={At least 7 detectors fail}.
Option D is correct answer .
C)
Required data is given by
Detectors numbers are 3,4,11,15
We have to obtained probability is
P(Detectors 3,4,11,15 fails)= 0.8^11 * 0.2^4.
Option D is correct answer .
D)
Required information is given by
probability 11 detectors is work and 4 detectors are fail than
Here,
Probability is
=P(Any Four detector fails )
=(15 c 4) *(0.8) ^(11 )*(0.2)^(4).
Option is C correct answer .