In: Statistics and Probability
Solution :
Given that,
mean = = 130
standard deviation = = 33.7
a ) P (120 < x < 171 )
P ( 120 - 130 / 33.7) < ( x - / ) < ( 171 - 130 / 33.7)
P ( - 10 / 33.7 < z < 41 / 33.7 )
P (-0.30 < z < 1.22)
P ( z < 1.22 ) - P ( z < - 0.30)
Using z table
= 0.8888 - 0.3821
= 0.5067
Probability = 0.5067
b ) n = 32
= 130
= / n = 33.7 32 = 5.9574
P (120 < < 171 )
P ( 120 - 130 / 5.9574) < ( - / ) < ( 171 - 130 /5.9574)
P ( - 10 / 5.9574 < z < 41 / 5.9574 )
P (-0.30 < z < 6.88)
P ( z < 6.88 ) - P ( z < - 1.68)
Using z table
= 1 - 0.0465
= 0.9535
Probability = 0.9535
c ) Option D ) is correct. D. Part (b) because the seat performance for a sample of pilots is more important.