Question

A Private Poly Clinic in City wish to develop software to automate their Patient Monitoring system for storing the details of the patients visited the clinic. Develop a system to meet the following requirements:

1. Develop an algorithm, flow chart and write a C program to read the gender of

patients and fees to be paid by them as shown in the below table. Calculate the

total fees paid by the female and male patients separately and display them

with appropriate statements.

  

Patient Id	Fees in (OMR)	Gender
P001	15	M
P002	10	F
P003	20	M
P004	8	F
P005	12	M

2. Read the fees paid by ‘N’ patients into a one dimensional array in random order. Develop an algorithm, flow chart and write a C program to arrange the fees read in ascending order. Display the result with appropriate statements.

3. Develop an algorithm, flow chart and write a C program to read the name of a patient which has a multi word and display it and the acromatic string of the name.

Sample Output : Name : Khamis Al Araimi

                           Acromatic String: AKAA

4. The clinic wish to give 15% discount on the fees to be paid by the patients whose age is above 60. Develop an algorithm, flow chart and write a C program to read age of the patient and calculate the fees after the discount by writing a function with argument. Display the result with appropriate statements.

Answer 1

Hello student in above stated question we have 4 parts as mentioned and i am going to solve one by one each. If you have any query please let me know and rate the answer

1). Displaying total fees paid by male and female patients along with there gender

Flow chart

Algorithm

read number of patients

nop=n

for i=1 to nop

{

read patients gender

read patients fee

if gender equals to male

fee_of_male increment by 1

else

fee_of_female increment by 1

}

display male patients fee

display female patients fee

C Program

#include <stdio.h>

int main()
{ char gender;
float fee=0,total_fee_male=0,total_fee_female=0;
int nop; // total number of patients
printf("enter a number of patients \n");
scanf("%d",&nop);

  
for (int i=0;i<nop;i++)
{
printf("Enter patients gender\n");
scanf("%c",&gender);

printf("Enter of patients fee\n");
scanf("%f",&f);

if ((gender=='m')||(gender=='M'))
{

total_fee_male= total_fee_male + fee;   
}
  
else
{
total_fee_female = total_fee_female + fee;
}
}
printf("fees paid by male %f /n", total_fee_male);
printf("fees paid by female %f /n", total_fee_male);


return 0;
}

2) Fees in ascending order

Flow chart

Algorithm

read number of patients

nop =n

for i =1 to nop

{

read patients fees

}

for i=1 to nop

{

for j=i+1 to nop

{ temp= fee[i]

fee[i]= fee[j]

fee[j] = fee[i]

}

}

display fees in ascending order

C Program

#include <stdio.h>

int main ()
{int n,i,j;
printf ("enter a no.of patients \n");
scanf ("%d", &n);
float f[n],t;
for (i = 0; i < n; i++)
{
printf("enter a fee patients \n");
scanf("%f",&f[i]);
}

for (i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
if(f[i]>f[j])
{
t=f[i];
f[i]=f[j];
f[j]=t;
}
}
}

printf("fees are arranged in ascending order \n");
for ( i = 0; i < n; i++)
{
  
printf("%f \n",f[i]);
}
  
return 0;
}

3)  Acromatic string

Flowchart

Algorithm

var i=0

read name of patient

display name [0]

while name[i] not equal to null

{

if name[i] equals to white space

display name[i]

increment i by 1

}

C program

#include <stdio.h>

int main()
{
char name[100];
int i=0;
printf("Enter name of a patient \n");
gets(name);

printf("%c",name[0]);
while (name [i]!='\0')
{
if(name[i]==' ')
{
i++;
printf("%c",name[i]);
}
i++;
}
getch();

return 0;
}

4) 15% discount

Flow chart

C program

#include <stdio.h>

void discount (int a, float f)
{
if (a>60)
{ float d;
d=f * 0.15;
f=f-d;
printf("fees to be paid after discount \n");
printf("%f",f);
}

else
{
printf("fees to be paid %f \n", f);
printf("%f",f);
}
}   
  

int main()
{ void discount(int a,float f);
int age;
float fee;
printf("Enter a patients age \n");
scanf("%d",&age);
  
printf("Enter a patients fee \n");
scanf("%f",&fee);
  
void discount(age,fee);




return 0;
}