In: Statistics and Probability
GPAs at CCSU are normally distributed with a mean of 2.34 and a standard deviation of 0.49. Find the Z-score for a GPA of 2.93.
mean = = 2.34
standard deviation = = 0.49
x = 2.93
Using z-score formula,
z = x - /
z = 2.93 - 2.34 / 0.49
z = 1.20