Two identical twins hold on to a rope, one at each end, on a smooth, frictionless...

Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the center of the rope (the center of mass of the two-body system) and perpendicular to the ice. The mass of each twin is 78.0 kg. The rope of negligible mass is 4.0 m long and they move at a speed of 4.90 m/s.

(a) What is the magnitude, in kg · m²/s, of the angular momentum of the system comprised of the two twins?

(b) They now pull on the rope and move closer to each other so that the rope between them is now half as long. Determine the speed, in m/s, with which they move now.

(c) The two twins have to do work in order to move closer to each other. How much work, in joules, did they do? This is the same as the change in kinetic energy.

Solutions

Expert Solution

The reason we are able to conserve angular momentum is because there is no external torgue acting on the system as the floor is frictionless.

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genius_generous answered 1 month ago

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