Question

Assignment
(1). In a city 25% of the people reads punch newspaper, 20% reads guidance. newspaper, 13% reads times newspaper, 10% reads both punch and guidance , 8% reads punch and time and 4% reads all three. If a person from this city is selected at random, what is the probability that he or she does not read any of this papers?
(2). In a community 32% of the population are male cassava farmers and 27% are female cassava farmers. what percentage of this community are cassava farmers?

Answer 1

1)

25% of the people reads punch newspaper.

P(punch) = 0.25

20% reads guidance.

P(guidance) = 0.20

13% reads times.

P(times) = 0.13

10% reads both punch and guidance.

8% reads both punch and time.

4% reads all three.

Since 4% reads all three newspapers, this 4% also reads both guidance and time.

Hence,

Let us first find percentage of people who does not read any of the newspaper.

We know that,

Let us denote punch by 'p', guidance by 'g' and time by 't' for rest of the work.

Find union of p, g and t using following formula:

Hence if a person is selected randomly then probability that he or she does not read any of the newspaper is 0.6

2)

Male cassava farmers = 32%

Female cassava farmers = 27%

Male and female are mutually exclusive and exhaustive events.

(i.e. no one can be both male and female at the same time and population is made up of males and females)

Hence, Total number of cassava farmers = number of male cassava farmers + number of female cassava farmers.

Hence total percentage of cassava farmers = percentage of male cassava farmers + percentage of female cassava farmers

Therefore, total percentage of cassava farmers = 32 + 27 = 59%