Question

In: Chemistry

Calculated pH of a solution that contains 0.30 M NH4OH

Expert Solution

NH4OH is weak base

Kb = 1.8*10^-5

NH4OH --------------------> NH4^+ (aq) + OH^-

I 0.3 0 0

C -x +x +x

E 0.3-x +x +x

Kb = [NH4^+][OH^-]/[NH4OH]

1.8*10^-5 = x*x/0.3-x

1.8*10^-5 *(0.3-x) = x^2

x = 0.0023

[OH^-] = x = 0.0023M

POH = -log[OH^-]

= -log0.0023

= 2.6383

PH = 14-POH

= 14-2.6383

= 11.3617 >>>>>answer

queen_honey_blossom answered 2 years ago

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