Question

In: Physics

A 0.300-kg ice puck, moving east with a speed of 5.84 m/s , has a head-on...

A 0.300-kg ice puck, moving east with a speed of 5.84 m/s , has a head-on collision with a 0.990-kg puck initially at rest. Assume that the collision is perfectly elastic.

A) What is the speed of the 0.300-kg puck after the collision?

Express your answer to three significant figures and include the appropriate units.

B) What is the direction of the velocity of the 0.300-kg puck after the collision? East or West?

C)

What is the speed of the 0.990-kg puck after the collision?

Express your answer to three significant figures and include the appropriate units.

D) What is the direction of the velocity of the 0.990-kg puck after the collision? East or West?

Solutions

Expert Solution

During collision momentum is conserved

Initial momentum =Final momentum

----------(1)

=====================

Given that collision is elastic, so kinetic energy is conserved

Initial kinetic energy = Final kinetic energy

Put (1) in the above equation

Multiply all terms with 0.99

Solve the quadratic equation using a calculator

A) What is the speed of the 0.300-kg puck after the collision?

ANSWER:

======================

B) What is the direction of the velocity of the 0.300-kg puck after the collision? East or West?

v1 is negative, so after collision 0.300kg puck is moving West

ANSWER:

==========================

Put value of v1 in (1)

C)What is the speed of the 0.990-kg puck after the collision?

ANSWER:

D) What is the direction of the velocity of the 0.990-kg puck after the collision? East or West?

v2 is positive, so after collision 0.990kg puck is moving East

ANSWER:

==========================

genius_generous answered 8 months ago
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