In: Advanced Math
Below is a proof of Theorem 4.1.1 (b): For the zero vector ⃗0 in any vector space V and k ∈ R, k⃗0 = ⃗0.
Justify for each of the eight steps why it is true.
k⃗0+k⃗0=k(⃗0+⃗0)
= k ⃗0
k⃗0 is in V
and therefore −(k⃗0) is in V .
It follows that (k⃗0 + k⃗0) + (−k⃗0) = (k⃗0) + (−k⃗0)
and thus k⃗0 + (k⃗0 + (−k⃗0)) = (k⃗0) + (−k⃗0).
We conclude that k⃗0 + ⃗0 = ⃗0
and so k⃗0 = ⃗0, as desired.