Question

A pitched baseball (m=0.3 kg) reaches a catcher’s glove travelling at a velocity of 28 m/s. Calculate the ball’s: A) momentum, B) kinetic energy. How much impulse is required to catch the ball? If the hand moves backward 32cm while the person is catching it, what is the average force applied to the ball? How much time will it take before the ball stops? What is the average power of this contact?

Answer 1

Concept - impulse is equal to change in momentum. Force is equal to rate of change of momentum. Power is equal to energy divided by time. We use this to find the required solutions as shown below***************************************************************************************************
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A) P = mu , V=28m/s = 8.4 lcg.mls K = 1/2 mu? = [117.65 B) c) Impulse - AP - PF - Pi = 0 - 8:41gmls - - 8.4 kgm/s So, magnitude = 18.4 kg. mis Sif sign is needed I put a minus sign D) W - OKE W = AKE ) -Fd=ook 3 -F(0.32m) - - 197.65 3 F = 1367.50 Sif sign is needed put a minus sign F - (DPI At = 8.4kgimis at 5) ot = 2: 29x10-2%s Pang = 45 - 0- => [Parg) = 5145W o-k At 0-147.65 o - 117.65 At -