Question

In: Statistics and Probability

Imagine you performed a “beer goggling” experiment and randomly assigned participants to drink either 0, 1,...

Imagine you performed a “beer goggling” experiment and randomly assigned participants to drink either 0, 1, or 3 beers, and then had all participants rate the attractiveness of the same fellow college student on a scale from 0 to 50, with higher scores indicating greater perceived attractiveness. There was a total of 21 participants in this study, divided evenly among the three coding conditions. Assume p < .05. Use these data to answer the following questions.

Group

/ Mean Attractiveness Rating

0 beer =

21.57

1 beer

= 26.57

3 beers

= 35.71

Source SS df MS F
Between 720.096 2 360.048 21.54
Within 300.857 18 16.714

A. in a post-hoc what is HSD value and what is the effect size of this data?

thank you for the help

Solutions

Expert Solution

Let's perform Tukey's Post hoc HSD test for above three groups

M0 = group with 0 beer

M1 = group with 1 beer

M3 = group with 3 beers

From above Anova Tales,

MSwithin =16.714;

M0 = 21.57;

M1 = 26.57;

M3 = 35.71;

dfwithin = 18;

n = 7(21 participants are equally divided into 3 groups)

Now, formula for HSD statistic is:

Where:

  • Mi – Mj is the difference between the pair of means. to calculate this, M,i should be larger than Mj
  • MSw is the Mean Square Within, and n is the number in the group or treatment

Applying Above formula we get,

Now, HSD(M3 vs M0) = 9.150

Similarly, HSD(M3 vs M1) = 5.915

HSD(M1 vs M0) = 3.235

From Tukey critical value table, HSD score df =18 and n = 7 for alpha = 0.05 is: 4.67

Now HSD values of M3 vs M1 and M3 vs M0is more than HSD score from table. Hence both the means are significantly different. So, M3-M1 and M3-M0 are significant.

On the other hand, HSD for M1 vs M0 is less than critical score. Hence we can say that mean for M1 and M0 is significantly same.


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