Question

In: Physics

A turntable rotating 33 rev/m slows to a stop in 10s. If the acceleration is constant,...

A turntable rotating 33 rev/m slows to a stop in 10s. If the acceleration is constant, the number of revolutions through which the turntable rotates in the 10 is?

A. 7.8

B. 1.4

C. 12.2

D. 2.7

E 6.1

Solutions

Expert Solution

Initial rotational speed of the turntable = N₁ = 33 rev/min

Initial angular speed of the turntable = ₁

₁ = 3.455 rad/s

Final angular speed of the turntable = ₂ = 0 rad/s (Comes to a stop)

Time taken by the turntable to stop = T = 10 sec

Angular acceleration of the table =

₂ = ₁ + T

0 = 3.455 + (10)

= -0.3455 rad/s²

Negative as it is deceleration.

Angle through which the turntable rotates in 10 sec =

= ₁T + T²/2

= (3.455)(10) + (-0.3455)(10)²/2

= 17.275 rad

Number of revolution made by the turntable in 10 sec = n

n = 2.7 rev

Number of revolutions through which the turntable rotates in 10 sec = 2.7 rev

genius_generous answered 3 months ago

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