Question

In: Advanced Math

3) Determine the longest interval in which the given initial value problem is certain to have...

3) Determine the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution. Do not attempt to find the solution t(t − 4)y" + 3ty' + 4y = 2 = 0, y(3) = 0, y'(3) = −1.

4) Consider the ODE: y" + y' − 2y = 0. Find the fundamental set of solutions y1, y2 satisfying y1(0) = 1, y'1 (0) = 0, y2(0) = 0, y'2 (0) = 1.

Solutions

Expert Solution


Related Solutions

Determine the unique solution of the given initial value problem that is valid in any interval...
Determine the unique solution of the given initial value problem that is valid in any interval not including the singular point.               4x2 y’’ + 8xy’ + 17y = 0;             y(1) = 2, y’ (1) = 2(31/2 )− 1 please show all steps
Solve the given initial-value problem. X' = 1   −1 1   3 X + t t +...
Solve the given initial-value problem. X' = 1   −1 1   3 X + t t + 1 , X(0) = 9 8 X(t) =
1) Solve the given initial-value problem. (x + y)2 dx + (2xy + x2 − 3)...
1) Solve the given initial-value problem. (x + y)2 dx + (2xy + x2 − 3) dy = 0,   y(1) = 1 2) Find the general solution of the given differential equation. x dy/dx + (4x + 1)y = e−4x y(x) = Give the largest interval over which the general solution is defined. (Think about the implications of any singular points. Enter your answer using interval notation.) Determine whether there are any transient terms in the general solution. (Enter the transient...
Solve the given initial-value problem. y'' + y = 0,    y(π/3) = 0,    y'(π/3) = 4
Solve the given initial-value problem. y'' + y = 0,    y(π/3) = 0,    y'(π/3) = 4
. Solve the Initial value problem by using Laplace transforms: ? ′′ + 3? ′ +...
. Solve the Initial value problem by using Laplace transforms: ? ′′ + 3? ′ + 2? = 6? −? , ?(0) = 2 ? ′ (0) = 8
Consider the following initial value problem: ?? − 2?? = √? − 2? + 3 ??...
Consider the following initial value problem: ?? − 2?? = √? − 2? + 3 ?? ?(0) = 6 1. Write the equation in the form ?? ?? = ?(?? + ?? + ? ), where ?, ?, ??? ? are constants and ? is a function. 2. Use the substitution ? = ?? + ?? + ? to transfer the equation into the variables ? and ? only. 3. Solve the equation in (2). 4. Re-substitute ? = ??...
1) Find the solution of the given initial value problem and describe the behavior of the...
1) Find the solution of the given initial value problem and describe the behavior of the solution as t → +∞ y" + 4y' + 3y = 0, y(0) = 2, y'(0) = −1. 2) Find a differential equation whose general solution is Y=c1e2t + c2e-3t 3) Determine the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution. Do not attempt to find the solution t(t − 4)y" + 3ty' + 4y...
Calculate the Euler method approximation to the solution of the initial value problem at the given...
Calculate the Euler method approximation to the solution of the initial value problem at the given x-values. Compare your results to the exact solution at these x-values. y' = y+y^2; y(1) = -1, x = 1.2, 1.4, 1.6, 1.8
3. Given the initial rate data for the reaction A + B –––> C, determine the...
3. Given the initial rate data for the reaction A + B –––> C, determine the rate expression for the reaction. [A], M [B], M Δ [C]/ Δ t (initial) M/s 0.215 0.150 5.81 x 10–4 0.215 0.300 1.16 x 10–3 0.430 0.150 2.32 x 10–3 A) (Δ[C]/Δt) = 1.80 x 10–2 M –1 s –1 [A][B] B) (Δ[C]/Δt) = 3.60 x 10–2 M –1 s –1 [A][B] C) (Δ[C]/Δt) = 1.20 x 10–1 M –2 s –1 [A][B]2 D)...
Solve the following initial value problem over the interval from t = 0 to 2 where...
Solve the following initial value problem over the interval from t = 0 to 2 where y(0) = 1 using the following methods. dy/dt=y*t^2−1.1y a) Analytical method b) Euler's method with h=0.5 at t=2 c) Euler's method with h=0.25 at t=2 d) Midpoint method with h=0.5 at t=2 e) Fourth-order Runge-Kutta method with h=0.5 at t=2 f) Display all yor results obtained above on the same graph
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT