Question

Chickens having a mass of 5 kg are immersion frozen in propylene glycol at -30°C (ρ=1068 kg/m^3). If the volume of each vacuum packaged bird is about 6000 cm^3, what force must be applied to each bird to keep it at mid-depth in the 1-m deep tank?

Answer 1

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There will be two forces acting on the chicken:

1. Weight of the chicken acting downwards.
2. Buoyant force acted upon the chicken by the fluid (propylene glycol) upwards.

Hence the net force acting on the chicken is given by Buoyant force - Weight of the chicken.

The direction of this net force will be upwards. Hence to hold the chicken at a place, immersion force should be equal to the net force.

We know that, Weight of the chicken is given by, W= mg = 5 kg x 9.8 m/s²= 49 N.

Buoyant force is given by the Weight of the fluid displaced by the chicken,

1 cm³= 10^-6 m³

Therefore,  immersion force applied to each bird to keep it at mid-depth is given by,

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