In: Economics
The Game Reserve Management aims to access the vehicle’s usage
to sustain it’s operations (assuming 10 km =1litre). A study
reveals that the demand for the vehicle has fluctuated per week as
shown below
Trips per week 5 6 7 8 9 10
Number of days 48 72 64 60 96 60
17. What is the likely demand for this van in the next 13 week period? use the following random numbers to foresee the future 88,44, 56, 31,04,37,16,73,31, 10, 82, 59, 82 *
The data that is provided is:
Trips per week | Number of days |
5 | 48 |
6 | 72 |
7 | 64 |
8 | 60 |
9 | 96 |
10 | 60 |
Run an OLS regression of "Trips per week" against "Number of days". The result is:
Trips per week | Number of days | SUMMARY OUTPUT | |||||||||
5 | 48 | ||||||||||
6 | 72 | Regression Statistics | |||||||||
7 | 64 | Multiple R | 0.418978349 | ||||||||
8 | 60 | R Square | 0.175542857 | ||||||||
9 | 96 | Adjusted R Square | -0.030571429 | ||||||||
10 | 60 | Standard Error | 1.899210362 | ||||||||
Observations | 6 | ||||||||||
ANOVA | |||||||||||
df | SS | MS | F | Significance F | |||||||
Regression | 1 | 3.072 | 3.072 | 0.851677294 | 0.408306804 | ||||||
Residual | 4 | 14.428 | 3.607 | ||||||||
Total | 5 | 17.5 | |||||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | ||||
Intercept | 4.3 | 3.55309724 | 1.210211742 | 0.292820642 | -5.564979442 | 14.16497944 | -5.564979442 | 14.16497944 | |||
Number of days | 0.048 | 0.052012018 | 0.922863638 | 0.408306804 | -0.096408512 | 0.192408512 | -0.096408512 | 0.192408512 |
Thus, the OLS regression equation is: Trips per Week = 4.3 + 0.048*Number of days
Thus, for the given random numbers for the next 13 weeks, the likely demand for the van is:
Number of days |
Predicted Trips per week (rounded off to nearest integer) Predicted Trips per week = 4.3 + 0.048*Number of days |
88 | 9 |
44 | 6 |
56 | 7 |
31 | 6 |
4 | 4 |
37 | 6 |
16 | 5 |
73 | 8 |
31 | 6 |
10 | 5 |
82 | 8 |
59 | 7 |
82 | 8 |