At 700

Expert Solution

2SO₂(g) + O₂(g) 2SO₃(g)

Equilibrium constant for the above reaction is = 0.0152 ----(1)

The reverse of the above chemical reaction is 2SO₃(g) 2SO₂(g) + O₂(g)

The euilibrium constant for this equilibrium reaction is

From (1)

Therefore numerical value of the equilibrium constant for the reverse reaction is 65.8

queen_honey_blossom answered 1 year ago

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