Question

In: Statistics and Probability

In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7%...

In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least one prescription medication (based on data from “Use of Prescription and Over-the-Counter Medications and Dietary Supplements Among Older Adults in the United States,” by Qato et al., Journal of the American Medical Association, Vol. 300, No. 24). Use a 0.01 significance level to test the claim that more than 3/4 of adults use at least one prescription medication.

Solutions

Expert Solution

Since n=3005 and and population proportion=0.75

The hypotheses are

Rejection region :

Since n>>>30 hence Z test statistic is applicable here as

reject Ho if Z calculated us >Z0.01=2.33

Test statistic:

P-value:

P-value associated with Z core calculated is computed using the Z table shown below

the p-value is approximately equal to zero.

conclusion:

Since the Z score calculated >>>Z critical at 0.01 level of significance and p-value<<0.01 hence we reject the null hypothesis and conclude that we have enough evidence to support the claim.

The Z table is shown below:


Related Solutions

In a survey of 3470 adults aged 57 through 85​ years, it was found that 82.3​%...
In a survey of 3470 adults aged 57 through 85​ years, it was found that 82.3​% of them used at least one prescription medication. Complete parts​ (a) through​ (c) below. a. How many of the 3470 subjects used at least one prescription​ medication? nothing ​(Round to the nearest integer as​ needed.) b. Construct a​ 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. nothing​%less thanpless than nothing​% ​(Round...
In a survey of 3276 adults aged 57 through 85​ years, it was found that 88.4​%...
In a survey of 3276 adults aged 57 through 85​ years, it was found that 88.4​% of them used at least one prescription medication. Complete parts​ (a) through​ (c) below. a. How many of the 3276 subjects used at least one prescription​ medication? ​(Round to the nearest integer as​ needed.) b. Construct a​ 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. ​__% < p < __%(Round to...
In a survey of 3025 adults aged 57 through 85​ years, it was found that 85.2​%...
In a survey of 3025 adults aged 57 through 85​ years, it was found that 85.2​% of them used at least one prescription medication. Complete parts​ (a) through​ (c) below. a. How many of the 3025 subjects used at least one prescription​ medication? ​(Round to the nearest integer as​ needed.) b. Construct a​ 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. = %<p< % ​(Round to one...
Q4. In a survey of 3272 adults aged 57 through 85​ years, it was found that...
Q4. In a survey of 3272 adults aged 57 through 85​ years, it was found that 81.1​% of them used at least one prescription medication. b. Construct a​ 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. nothing​%less than<pless than<nothing​% ​(Round to one decimal place as​ needed.) What do the results tell us about the proportion of college students who use at least one prescription​ medication? A.The results...
A survey of 500 randomly selected adults found that 57% say that they would take a...
A survey of 500 randomly selected adults found that 57% say that they would take a ride in a fully self-driving car. The 95% confidence interval for the true proportion of all adults who would take a ride in a full self-driving car is found to be (0.5266, 0.6134). Can we conclude that the majority of all adults would take a ride in a fully self-driving car? Yes; Since the confidence interval limits are both greater than 50%, we can...
Adults aged 18 years old and older were randomly selected for a survey on obesity. Adults...
Adults aged 18 years old and older were randomly selected for a survey on obesity. Adults are considered obese if their body mass index (BMI) is at least 30. The researchers wanted to determine if the proportion of women in the south who are obese is less than the proportion of southern men who are obese. The results are shown in the table below. # who are obese sample size Men 42,769 155,525 Women 67,169 248,775 At the1% level of...
The Pew Research Center recently conducted a survey of 1007 U.S. adults and found that 85%...
The Pew Research Center recently conducted a survey of 1007 U.S. adults and found that 85% of those surveyed know what Twitter is. Using the survey results construct a 95% confidence interval estimate of the percentage of all adults who know what Twitter is. Round the percentages to the first decimal place. (c) Explain why it would or would not be okay for a newspaper to make this statement: “Based on results from a recent survey, more than 3 out...
Q1. A survey of 500 adults aged 18 – 29 years of age revealed that 285...
Q1. A survey of 500 adults aged 18 – 29 years of age revealed that 285 chose to eat fast food for dinner at least once in the past week. Find the sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week. (Hint: p ^ = x n , where x = # of people who have given characteristic (eat fast food) and n is sample size) Q2. Verify two conditions (...
In a survey of 1007 adults aged 18 to 74 living in a city, the prevalence...
In a survey of 1007 adults aged 18 to 74 living in a city, the prevalence of smokers was found to be 368. Build a 90% confidence interval for the proportion of smokers. Interpret the interval above. Build a 95% confidence interval for the proportion of smokers. Interpret the interval above. Compare with 90% CI.
In a random survey of 2221 adults aged 18 and older 689 of them said that...
In a random survey of 2221 adults aged 18 and older 689 of them said that football is their favorite sport to watch on television. Construct a 94% Confidence Interval for the true proportion of adults aged 18 and older for whom football is their favorite sport to watch on television. A (.2909, .3295) B (.2918, .3287) C (.3185. .3401) D (.3102, .3214)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT