In: Statistics and Probability
In one study of smokers who tried to quit smoking with nicotine patch therapy, 35 were smoking one year after treatment and 34 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking one year after the treatment. Do these results suggest that the nicotine patch therapy is noteffective?
The test statistic for this hypothesis test is _
Identify the P Value for this hypothesis test
SOLUTION:
From given data,
In one study of smokers who tried to quit smoking with nicotine patch therapy, 35 were smoking one year after treatment and 34 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking one year after the treatment.
EXPLANATION:
H0: Null Hypothesis: P < 0.5
HA: Alternative Hypothesis: P > 0.5
n = Sample Size =35+34 = 69
= Sample Proportion = 35/69 =0.5072
P = Population Proportion
Q = 1 - P = 1-0.5=0.5
= 0.06019
Test statistic is:
Z = (0.5072 - 0.5)/ 0.06019
= 0.11962
approx 0.12
Table of Area Under Standard Normal Curve gives area = 0.04776
So,
p - value = 0.5 - 0.04776 = 0.45224
Since p - value= 0.45224 is greater than = 0.10, the difference is not significant.
Fail to reject null hypothesis.
= 0.10
One Tail - Right Side Test
From Table, critical value of Z = 1.2816
Since the calculated value of Z = 0.11962 is critical value of Z = 1.2816, the difference is not significant. Fail to reject null hypothesis.