In: Statistics and Probability
At a gymnastics meet, three judges evaluate the balance beam performances of five gymnasts. The judges use a scale of 1 to 10, where 10 is a perfect score. A statistician wants to examine the objectivity and consistency of the judges. Assume scores are normally distributed. (You may find it useful to reference the q table.)
Judge 1 Judge 2 Judge 3
Gymnast 1 9.5 8.0 7.8
Gymnast 2 9.5 9.5 9.2
Gymnast 3 9.1 8.4 7.4
Gymnast 4 7.9 8.2 8.6
Gymnast 5 9.3 7.9 9.1
a-1. Construct an ANOVA table. (Round
intermediate calculations to at least 4 decimal places. Round
"SS", "MS", "p-value" to 4 decimal
places and "F" to 3 decimal places.)
ANOVA
Source of Variation SS df MS F p-value
Rows _______ ______ ______ ______ _______
Columns _______ ______ ______ ______ _______
Error _______ ______ ______ ______ _______
Total _______ ______
a-2. At the 5% significance level, can you conclude that average scores differ by judge?
a-3. Can you conclude that the judges seem inconsistent with their scoring?
b. At the 5% significance level, can you conclude that average scores differ by gymnast?
c. If average scores differ by gymnast, use
Tukey’s HSD method at the 5% significance level to determine which
gymnasts’ performances differ. (Negative values should be
indicated by a minus sign. Round intermediate calculations to at
least 4 decimal places. Round your answers to 2 decimal
places.)
Population Mean Difference Confidence Interval Does the mean score differ at the 5%
Significance level?
µ1-µ2 [ , ]
µ1-µ3 [ , ]
µ1-µ4 [ , ]
µ1-µ5 [ , ]
µ2-µ3 [ , ]
µ2-µ4 [ , ]
µ2-µ5 [ , ]
µ3-µ4 [ , ]
µ3-µ5 [ , ]
µ4-µ5 [ , ]
MINTAB used
a-1. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS", "MS", "p-value" to 4 decimal places and "F" to 3 decimal places.)
Analysis of Variance
Source |
DF |
SS |
MS |
F-Value |
P-Value |
Gymnast |
4 |
2.7493 |
0.6873 |
1.702 |
0.2418 |
Judge |
2 |
1.4093 |
0.7047 |
1.745 |
0.2350 |
Error |
8 |
3.2307 |
0.4038 |
||
Total |
14 |
7.3893 |
a-2. At the 5% significance level, can you conclude that average scores differ by judge?
a-3. Can you conclude that the judges seem inconsistent with their scoring?
b. At the 5% significance level, can you conclude that average scores differ by gymnast?
c. If average scores differ by gymnast, use Tukey’s HSD method at the 5% significance level to determine which gymnasts’ performances differ. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.)
Tukey Simultaneous Tests for Differences of Means
Difference |
Difference |
SE of |
Simultaneous |
T-Value |
Adjusted |
2 - 1 |
0.967 |
0.519 |
(-0.83, 2.76) |
1.86 |
0.405 |
3 - 1 |
-0.133 |
0.519 |
(-1.93, 1.66) |
-0.26 |
0.999 |
4 - 1 |
-0.200 |
0.519 |
(-1.99, 1.59) |
-0.39 |
0.994 |
5 - 1 |
0.333 |
0.519 |
(-1.46, 2.13) |
0.64 |
0.963 |
3 - 2 |
-1.100 |
0.519 |
(-2.89, 0.69) |
-2.12 |
0.298 |
4 - 2 |
-1.167 |
0.519 |
(-2.96, 0.63) |
-2.25 |
0.254 |
5 - 2 |
-0.633 |
0.519 |
(-2.43, 1.16) |
-1.22 |
0.741 |
4 - 3 |
-0.067 |
0.519 |
(-1.86, 1.73) |
-0.13 |
1.000 |
5 - 3 |
0.467 |
0.519 |
(-1.33, 2.26) |
0.90 |
0.889 |
5 - 4 |
0.533 |
0.519 |
(-1.26, 2.33) |
1.03 |
0.836 |
Individual confidence level = 99.14%
Tukey Simultaneous Tests for Differences of Means
Difference |
Difference |
Simultaneous |
Significance |
|||
µ1-µ2 |
-0.967 |
(-2.76, 0.83) |
No |
|||
µ1-µ3 |
0.133 |
(-1.66, 1.93) |
No |
|||
µ1-µ4 |
0.200 |
(-1.59, 1.99) |
No |
|||
µ1-µ5 |
-0.333 |
(-2.13, 1.46) |
No |
|||
µ2-µ3 |
1.100 |
(-0.69, 2.89) |
No |
|||
µ2-µ4 |
1.167 |
(-0.63, 2.96) |
No |
|||
µ2-µ5 |
0.633 |
(-1.16, 2.43) |
No |
|||
µ3-µ4 |
0.067 |
(-1.73, 1.86) |
No |
|||
µ3-µ5 |
-0.467 |
(-2.26, 1.33) |
No |
|||
µ4-µ5 |
-0.533 |
(-2.33, 1.26) |
No |