In: Statistics and Probability
At a gymnastics meet, three judges evaluate the balance beam performances of five gymnasts. The judges use a scale of 1 to 10, where 10 is a perfect score. A statistician wants to examine the objectivity and consistency of the judges. Assume scores are normally distributed. (You may find it useful to reference the q table.)
Judge 1 Judge 2 Judge 3
Gymnast 1 9.5 8.0 7.8
Gymnast 2 9.5 9.5 9.2
Gymnast 3 9.1 8.4 7.4
Gymnast 4 7.9 8.2 8.6
Gymnast 5 9.3 7.9 9.1
a-1. Construct an ANOVA table. (Round
intermediate calculations to at least 4 decimal places. Round
"SS", "MS", "p-value" to 4 decimal
places and "F" to 3 decimal places.)
ANOVA
Source of Variation SS df MS F p-value
Rows _______ ______ ______ ______ _______
Columns _______ ______ ______ ______ _______
Error _______ ______ ______ ______ _______
Total _______ ______
a-2. At the 5% significance level, can you conclude that average scores differ by judge?
a-3. Can you conclude that the judges seem inconsistent with their scoring?
b. At the 5% significance level, can you conclude that average scores differ by gymnast?
c. If average scores differ by gymnast, use
Tukey’s HSD method at the 5% significance level to determine which
gymnasts’ performances differ. (Negative values should be
indicated by a minus sign. Round intermediate calculations to at
least 4 decimal places. Round your answers to 2 decimal
places.)
Population Mean Difference Confidence Interval Does the mean score differ at the 5%
Significance level?
µ1-µ2 [ , ]
µ1-µ3 [ , ]
µ1-µ4 [ , ]
µ1-µ5 [ , ]
µ2-µ3 [ , ]
µ2-µ4 [ , ]
µ2-µ5 [ , ]
µ3-µ4 [ , ]
µ3-µ5 [ , ]
µ4-µ5 [ , ]
MINTAB used
a-1. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS", "MS", "p-value" to 4 decimal places and "F" to 3 decimal places.)
Analysis of Variance
| 
 Source  | 
 DF  | 
 SS  | 
 MS  | 
 F-Value  | 
 P-Value  | 
| 
 Gymnast  | 
 4  | 
 2.7493  | 
 0.6873  | 
 1.702  | 
 0.2418  | 
| 
 Judge  | 
 2  | 
 1.4093  | 
 0.7047  | 
 1.745  | 
 0.2350  | 
| 
 Error  | 
 8  | 
 3.2307  | 
 0.4038  | 
||
| 
 Total  | 
 14  | 
 7.3893  | 
a-2. At the 5% significance level, can you conclude that average scores differ by judge?
a-3. Can you conclude that the judges seem inconsistent with their scoring?
b. At the 5% significance level, can you conclude that average scores differ by gymnast?
c. If average scores differ by gymnast, use Tukey’s HSD method at the 5% significance level to determine which gymnasts’ performances differ. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round your answers to 2 decimal places.)
Tukey Simultaneous Tests for Differences of Means
| 
 Difference  | 
 Difference  | 
 SE of  | 
 Simultaneous  | 
 T-Value  | 
 Adjusted  | 
| 
 2 - 1  | 
 0.967  | 
 0.519  | 
 (-0.83, 2.76)  | 
 1.86  | 
 0.405  | 
| 
 3 - 1  | 
 -0.133  | 
 0.519  | 
 (-1.93, 1.66)  | 
 -0.26  | 
 0.999  | 
| 
 4 - 1  | 
 -0.200  | 
 0.519  | 
 (-1.99, 1.59)  | 
 -0.39  | 
 0.994  | 
| 
 5 - 1  | 
 0.333  | 
 0.519  | 
 (-1.46, 2.13)  | 
 0.64  | 
 0.963  | 
| 
 3 - 2  | 
 -1.100  | 
 0.519  | 
 (-2.89, 0.69)  | 
 -2.12  | 
 0.298  | 
| 
 4 - 2  | 
 -1.167  | 
 0.519  | 
 (-2.96, 0.63)  | 
 -2.25  | 
 0.254  | 
| 
 5 - 2  | 
 -0.633  | 
 0.519  | 
 (-2.43, 1.16)  | 
 -1.22  | 
 0.741  | 
| 
 4 - 3  | 
 -0.067  | 
 0.519  | 
 (-1.86, 1.73)  | 
 -0.13  | 
 1.000  | 
| 
 5 - 3  | 
 0.467  | 
 0.519  | 
 (-1.33, 2.26)  | 
 0.90  | 
 0.889  | 
| 
 5 - 4  | 
 0.533  | 
 0.519  | 
 (-1.26, 2.33)  | 
 1.03  | 
 0.836  | 
Individual confidence level = 99.14%
Tukey Simultaneous Tests for Differences of Means
| 
 Difference  | 
 Difference  | 
 Simultaneous  | 
 Significance  | 
|||
| 
 µ1-µ2  | 
 -0.967  | 
 (-2.76, 0.83)  | 
 No  | 
|||
| 
 µ1-µ3  | 
 0.133  | 
 (-1.66, 1.93)  | 
 No  | 
|||
| 
 µ1-µ4  | 
 0.200  | 
 (-1.59, 1.99)  | 
 No  | 
|||
| 
 µ1-µ5  | 
 -0.333  | 
 (-2.13, 1.46)  | 
 No  | 
|||
| 
 µ2-µ3  | 
 1.100  | 
 (-0.69, 2.89)  | 
 No  | 
|||
| 
 µ2-µ4  | 
 1.167  | 
 (-0.63, 2.96)  | 
 No  | 
|||
| 
 µ2-µ5  | 
 0.633  | 
 (-1.16, 2.43)  | 
 No  | 
|||
| 
 µ3-µ4  | 
 0.067  | 
 (-1.73, 1.86)  | 
 No  | 
|||
| 
 µ3-µ5  | 
 -0.467  | 
 (-2.26, 1.33)  | 
 No  | 
|||
| 
 µ4-µ5  | 
 -0.533  | 
 (-2.33, 1.26)  | 
 No  |