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A buffer contains 0.11 mol of propionic acid (C2H5COOH) and 0.17 mol of sodium propionate (C2H5COONa)...

A buffer contains 0.11 mol of propionic acid (C2H5COOH) and 0.17 mol of sodium propionate (C2H5COONa) in 1.20 L. What is the pH of this buffer?

What is the pH of the buffer after the addition of 0.02 mol of NaOH?

What is the pH of the buffer after the addition of 0.02 mol of HI?

Solutions

Expert Solution

no of moles of C2H5COOH = 0.11moles

molarity of C2H5COOH = no of moles/volume in L

                                    = 0.11/1.2   = 0.0917 M

no of moles of C2H5COONa = 0.17moles

molarity of C2H5COONa = no of moles/volume in L

                                    = 0.17/1.2   = 0.1417M

Pka of C2H5COOH   = 4.87

PH   = Pka + log[C2H5COONa]/[C2H5COOH]

       = 4.87 + log0.1417/0.0917

       = 4.87 + 0.189

       = 5.06>>>>answer

no of moles of C2H5COOH after addition of 0.02moles of NaOH = 0.11-0.02 = 0.09moles

no of moles of C2H5COONa after addition of 0.02moles of NaOH    = 0.17+0.02   = 0.19moles

PH   = Pka + log[C2H5COONa]/[C2H5COOH]

        = 4.87 + log0.19/0.09

        = 4.87 + 0.3245

        = 5.1945>>>>answer

no of moles of C2H5COOH after addition of 0.02moles of HCl = 0.11+0.02 = 0.13moles

no of moles of C2H5COONa after addition of 0.02moles of HCl    = 0.17-0.02   = 0.15moles

PH   = Pka + log[C2H5COONa]/[C2H5COOH]

        = 4.87 + log0.15/0.13

        = 4.87 + 0.06215

        = 4.932>>>>answer

queen_honey_blossom answered 9 months ago
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