In: Chemistry
Calculate the boiling point of a water solution at each concentration. |
Part A 0.225 m Express your answer using three decimal places.
SubmitMy AnswersGive Up Part B 3.78 m Express your answer using two decimal places.
SubmitMy AnswersGive Up Part C 4.33 m Express your answer using two decimal places.
SubmitMy AnswersGive Up Part D 7.77 m Express your answer using two decimal places.
SubmitMy AnswersGive Up |
A)
lets now calculate deltaTb
deltaTb = Kb*m
= 0.512*0.225
= 0.1152 oC
This is increase in boiling point
boiling point of pure liquid = 100.0 oC
So, new boiling point = 100 + 0.1152
= 100.1152 oC
Answer: 100.115 oC
B)
lets now calculate deltaTb
deltaTb = Kb*m
= 0.512*3.78
= 1.9354 oC
This is increase in boiling point
boiling point of pure liquid = 100.0 oC
So, new boiling point = 100 + 1.9354
= 101.9354 oC
Answer: 101.935 oC
C)
lets now calculate deltaTb
deltaTb = Kb*m
= 0.512*4.33
= 2.217 oC
This is increase in boiling point
boiling point of pure liquid = 100.0 oC
So, new boiling point = 100 + 2.217
= 102.217 oC
Answer: 102.217 oC
D)
lets now calculate deltaTb
deltaTb = Kb*m
= 0.512*7.77
= 3.9782 oC
This is increase in boiling point
boiling point of pure liquid = 100.0 oC
So, new boiling point = 100 + 3.9782
= 103.978 oC
Answer: 103.978 oC