Question

In: Chemistry

If you were to have performed a TLC analysis of ferrocene and acetylferrocenesamples using pure diethyl...

If you were to have performed a TLC analysis of ferrocene and acetylferrocenesamples using pure diethyl ether (rather than as the more polar solvent in a 1:1 mixture with the less polar petroleum ether), which of the two spots would have a greater Rf? Explain briefly.

Solutions

Expert Solution

TLC stands for Thin Layer Chromatography; it is an analytical technique in which we exploit each sample's affinity toward different polar/nonpolar solvents.

We use a stationary phase: a phase which does NOT moves, as the name implies. It is typically the "thin layer" or the "plate". It is commonly to use silica gel plates, which are polar, but any species could be used, such as paper.

We also use a mobile phase: as the name implies, this phase will "move" and will carry along the path all the components from the solvent. Many times, you will be able to split in several components the "mixture" of the sample. Therefore, they can be seen in the stationary phase (plate). Typically, we allow the mobile phase to go up to the "Rfinal" mark, or final reference. This is the distance travelled by the solvent (mobile phase). It starts at solvent level, it is R0, therefore.

Rf = distance traveled by sample / distance traveled by solvent

Then, "Rf" value allows us to understand the affinities of anaytes towards the solvent.

As Rf increases, this implies higher affinity toward the mobile phase ( since it is carried all along the mobile phase)

If Rf is low, this implies a low affinity toward the mobile phase; therefore higher affinity toward the stationary phase, since it sticks to the plate rather than travel upwards.

then:

ferrocene and acetylferrocene

Clearly

ferrocene is much more "nonpolar" than acetlferrocene

so the ferrocene will remain with mobile phase

that is

Ferrocene's Rf > acetlyferrocene Rf


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