Question

In: Statistics and Probability

Complete a 6-step hypothesis test using the following scenario: In 2012, the mean age of an...

Complete a 6-step hypothesis test using the following scenario:

In 2012, the mean age of an inmate on death row was 40.7 years, according to data from the U.S. Department of Justice. A sociologist wondered whether the mean age of a death row inmate has changed since then. She randomly selects 32 death row inmates and finds that their mean age is 38.9 with a standard deviation of 9.6. Test using a 0.01 significance level.

Solutions

Expert Solution

Solution :

= 40.7

= 38.9

S = 9.6

n = 32

This is the two tailed test .

The null and alternative hypothesis is ,

H0 :   = 40.7

Ha :    40.7

= 0.01

critical value for a two-tailed test is tc = 2.744

Test statistic = t

= ( - ) / S / n

= (38.9-40.7) /9.6 / 32

= -1.061

P(z <-1.061 ) = 0.297

P-value = 0.297

=0.01

p = 0.297 ≥ 0.01, it is concluded that the null hypothesis is not rejected.

There is not enough evidence to claim that the population mean \muμ is different than 40.7, at the 0.01 significance level.


Related Solutions

Complete a 6-step hypothesis test using the following scenario: In 2012, the mean age of an...
Complete a 6-step hypothesis test using the following scenario: In 2012, the mean age of an inmate on death row was 40.7 years, according to data from the U.S. Department of Justice. A sociologist wondered whether the mean age of a death row inmate has changed since then. She randomly selects 32 death row inmates and finds that their mean age is 38.9 with a standard deviation of 9.6. Test using a 0.01 significance level.
Complete a 6-step hypothesis test using the following scenario: The body mass index (BMI) of an...
Complete a 6-step hypothesis test using the following scenario: The body mass index (BMI) of an individual is a measure used to judge whether an individual is overweight or not. A BMI between 20 and 25 indicates normal weight. In a survey of 750 men and 750 women, the Gallup organization found that 203 men and 270 women were normal weight. Is this enough evidence to determine if there is a greater number of women at a normal weight than...
Complete a 6-step hypothesis test using the following scenario: Students at a college are randomly selected...
Complete a 6-step hypothesis test using the following scenario: Students at a college are randomly selected 217 student cars and they found that they had ages with a mean of 7.89 years and a standard deviation of 3.67 years. They also randomly selected 152 faculty cars and found that they had ages with a mean of 5.99 years and a standard deviation of 3.65 years. Using a 0.05 significance level, is there sufficient evidence to support the claim that student...
 Complete a hypothesis test involving your independent variable. Test the claim that the mean of...
 Complete a hypothesis test involving your independent variable. Test the claim that the mean of your independent variable is different then you guess (seethe “Set-Up” section of your project for your guess), using  = 0.05. Note: Because Minitab is using the same screen to perform both C.I. and H.T., Minitab is asking you to set (1-), the level of confidence and not  the level of significance of the test. If you want to perform a test at...
hypothesis statements using symbols for Two sided hypothesis test for the mean One sided hypothesis test...
hypothesis statements using symbols for Two sided hypothesis test for the mean One sided hypothesis test for the mean Two sided hypothesis test for variance One sided hypothesis test for variance Explain what each symbol you used above stands for
Hypothesis test. Using the p-value method,conduct a formal hypothesis test of the claim that the mean...
Hypothesis test. Using the p-value method,conduct a formal hypothesis test of the claim that the mean RBG of Type 2 diabetics is 13.5 mmol/dl or higher. Use = 0.01. Include the following in your written summary of the results: Your null and alternate hypotheses in the proper format using standard notation. The type of distribution you used ( or normal). The p-value and its logical relationship to (≤ or >). Your decision regarding the null hypothesis: reject or fail to...
6 step hypothesis tests using ANOVA: Levene Test and ANOVA: single factor Info: Concerned about Friday...
6 step hypothesis tests using ANOVA: Levene Test and ANOVA: single factor Info: Concerned about Friday absences, management examined the number of persons absent for each of the past three Fridays. Does this sample provide sufficient evidence to conclude there is a significant difference in the average number of absences? Use alpha = .05. Plant 1 Plant 2 Plant 3 Plant 4 19 17 27 22 24 20 32 27 20 16 27 25
This assignment is about correlations and test of hypothesis. For each test of hypothesis scenario, (a)...
This assignment is about correlations and test of hypothesis. For each test of hypothesis scenario, (a) formulate the null and alternative hypotheses, (b) indicate the test used, (c) state the p-value from the test results, and (d) provide your conclusion. In your conclusion, give a reason for rejecting or not rejecting the null and clearly state what it means in the context of the problem. Are there significant differences in current salary for men and women? Female Male $21,900.00 $57,000.00...
A large automobile insurance company wants to test the null hypothesis that the mean age in...
A large automobile insurance company wants to test the null hypothesis that the mean age in its population of policyholders is 50, against the alternative hypothesis that it is different from 50. In a random sample of 361 policyholders, the average age is 47.2 years, and the variance is 121 (squared years). The significance level is 5%. 1. What is the population? a. Bernoulli. Xi , i = 1,…,n are i.i.d. Bernoulli random variables with success probability p b. Normal....
Explain the following: Concepts of Hypothesis Testing Hypotheses Test for a population mean Hypothesis test for...
Explain the following: Concepts of Hypothesis Testing Hypotheses Test for a population mean Hypothesis test for a population proportion Test of normality Chi-Square Test for Independence
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT