Question

Estimate the footprint for a shell-and-tube heat exchanger from the following design data:

Area = 145 m

Hot side temperatures: in at 300°C, out at 195°C

Cold side temperatures: bfw at 105°C, mps at 184°C

Use 12 ft, 1-in OD tubes on a 1-1/4-in square pitch, use a single shell-and tube pass because of change of phase on shell side

Use a vapor space above boiling liquid = 3 times liquid volume

Answer 1

HT area of 1 tube = πDL = π(1/12)(12ft) = 3.142ft²

Number of tubes = (145m²)(3.2808ft/m)²(1/3.142ft²) = 497 tubes

 

Fractional area of the tubes = π/4(1/1.25)² = 0.5027

 

CSA_SHELL = (4)(777) = 3108in² ⇒ π/4D²_SHELL = 3108in²

D_SHELL = √(4)(3108in²)/π = 62.9in = 1.598m

Length of Heat Exchanger (2 + 12 + 2)ft = 16ft = 4.877m

Foot Print = 1.598 × 4.877m