Question

We observe a glancing collision between two billiard balls of the same mass. The first ball is incident at a speed of 6.36 m/s, strikes the second ball (initially at rest) and moves off with a speed of 5.54 m/s at an angle of 29.5

Answer 1

  Let mass of first ball (m1) = m .

   Mass of the second ball (m2) = m/2

.

               Initial velocity of m1 is : u1 = 6.36 m /s

.

               Initial velocity of m2 is : u2 = 5.54 m/ s

.

Final velocity of m1 :

.

                 .

                      = [6.36 ( m - m/2 ) + 2 (m/2) (5.54) ] / ( m + m/2)

.

                     =  ( 3.18 m + 5.54 m ) / 1.5 m

.

                       = ( 8.72) m / 1.5 m = 5.813 m/s

.

Final velocity of m2 is :

..

v2 = u2(m2