Question

Find z such that 85% of the standard normal curve lies to the left of z. (Round your answer to two decimal places.)
z =

Answer 1

We have given area to the left side of Z as 85 %

We convert the left side area into decimal = 0.8500

We search for area 0.8500

We do not have an area of 0.8500 inside the body of the table.

So we select the area which is very close to 0.8500

Area 0.8508 is very close to 0.8500

Z score for area 0.8508 = row headed 0.8508 + column headed 0.8508

Z score for area 0.8508 = 1.0 + .04

Z score for area 0.8508 = 1.04

Z score for area 0.8500 = Z score for area 0.8508 = 1.04

Final answer:-

Z = 1.04