Question

In: Biology

In elephants, pink skin is due to the mutant allele g, which is recessive to the...

In elephants, pink skin is due to the mutant allele g, which is recessive to the wild-type allele G, which gives grey skin. The curly tail phenotype is due to the mutant allele t, which is recessive to the wild-type allele T, which gives a straight tail. The two genes are located close together on the same chromosome. An elephant that is heterozygous for both genes was crossed to a pink, curly tailed elephant, and the following progeny were observed:


Phenotype Number Genotype Parental or recombinant Grey, straight tailed elephants 39 Pink, straight tailed elephants 12 Grey, curly tailed elephants 9 Pink, curly tailed elephants 30   

a) Fill out the table with the genotype for each class of offspring. Label each class as either parental or recombinant

b) Calculate the recombination frequency between the two genes.

c) The heterozygote used in the cross described above was produced by a mating of true-breeding elephants. What were the genotypes of the parents of the heterozygote?

d) Draw a diagram of the chromosome, showing the arrangement of the two genes in the heterozygote. Show both copies of the chromosom

Solutions

Expert Solution

The total answers is given below:

Please give a thumb up response if you find the answer helpful to you. Thank you.


Related Solutions

Miniature wings in Drosophila are due to an X-linked allele (Xm) that is recessive to the...
Miniature wings in Drosophila are due to an X-linked allele (Xm) that is recessive to the wild-type allele for normal long wings (X+). Sepia eyes are produced by an autosomal allele (se), which is recessive to the wild-type allele for red eyes (se+). A female that is homozygous for normal wings and has sepia eyes is crossed with a male that has miniature wings and is homozygous for red eyes. The F1 offspring are intercrossed to produce the F2 generation....
In elephants, the allele for the prehensile trunk, T is dominant over the allele for a...
In elephants, the allele for the prehensile trunk, T is dominant over the allele for a non-grasping trunk, t; the allele for floppy ears, E is dominant over the allele for pointy ears, e; and the allele for pointy tusks, P is dominant over the allele for blunt tusks. If you were to cross a trihybrid elephant with a pure-breeding elephant with a prehensile trunk, pointy ears, and blunt tusks, what proportion of the offspring would have a genotype of...
2. In panthers, black coat (g) is recessive to golden coat (G), pink eyes (b) is...
2. In panthers, black coat (g) is recessive to golden coat (G), pink eyes (b) is recessive to blue eyes (B), and short tail (l) is recessive to long tail (L). A female heterozygous for all three genes is test crossed to a homozygous recessive male and the following offspring were obtained: BGL 70 BgL 78 bGL 358 BGl 4 bgL 8 Bgl 344 bGl 70 bgl 68 a. How many genes are linked? b. Which groups are the parentals?...
The black color cost in hamsters is due to a dominant gene (B).. A recessive allele...
The black color cost in hamsters is due to a dominant gene (B).. A recessive allele (b) at this locus results in a brown coat when homozygous (b/b). However, neither coat color is expressed when the organism is homozygous for the allele (a) at a separate locus. The a/a genotype results in a white (albino) coat, regardless of the allele at the B locus. The wild-type allele (+) at the (a) locus allows normal coat coloration, whether the genotype is...
Red-green color blindness is due to an X-linked recessive allele in humans. A widow’s peak (a...
Red-green color blindness is due to an X-linked recessive allele in humans. A widow’s peak (a hairline that comes to a peak in the middle of the forehead) is due to an autosomal dominant allele. Consider the following family history: A man with a widow’s peak and normal color vision marries a color-blind woman with a straight hairline. The man’s father had a straight hairline, as did both of the woman’s parents. Use the family history to make predictions about...
A protein with a wild-type allele (Pwt) and protein with a mutant allele (Pm) are one...
A protein with a wild-type allele (Pwt) and protein with a mutant allele (Pm) are one amino acid in the position 12 of the protein chain. The mutant allele's sequence is 5'CTT whereras the wild-type allele's sequence is 5'CAT. Using an amino acid chart, find : Pwt in position #12 Pm in position #12
In a snail, an autosomal allele causing a banded shell (b) is recessive to the allele...
In a snail, an autosomal allele causing a banded shell (b) is recessive to the allele for unbanded shell (B). Genes at a different locus on the same chromosome determine the background color of the shell; here, yellow (y) is recessive to brown (Y). The genes for shell banding and background color have a recombination frequency of 0.25. A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a...
In mice the allele for blue coat color (B) pink coat color (b). The allele for...
In mice the allele for blue coat color (B) pink coat color (b). The allele for long tail (T) is dominant of the allele for short tail (t). 1) If alleles of the two genes Assort Independently, what types of gametes will BbTt mice produce? What is the expected frequency of each gamete among all gametes produced?
In rabbits, black hair depends on a dominant allele, B. and brown on a recessive allele,...
In rabbits, black hair depends on a dominant allele, B. and brown on a recessive allele, b. Short hair is due to a dominant allele, S, and long hair to a recessive allele, s. A short, black haired male rabbit who is homozygous dominant for both traits is mated with a brown, long haired female a. Write the genotype (in letters) of both parents. b. Draw the Punnett square below illustrating the cross of the parental rabbits. c. What percentage...
How does the environment play a role in changing the frequency of a mutant allele in...
How does the environment play a role in changing the frequency of a mutant allele in a population?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT