Question

In: Statistics and Probability

Beer shelf life is a problem for brewers and distributors because when beer is stored at...

Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorates. When the average furfuryl ether content reaches 6 μg per liter, a typical consumer begins to taste an unpleasant chemical flavor. At α = .05, would the following sample of 12 randomly chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold?

6.72 5.94 8.83 8.86 6.38 5.36 7.79 7.21 8.40 8.09 5.52 5.42
(a) For the following hypothesis

H0: μ ≤ 6 versus H1: μ > 6, what is the value of the test statistic? (Round your answer to 3 decimal places.)

  Test statistic   
(b) What is the p-value? (Round your answer to 4 decimal places.)
  p-value   
(c) At α = .05, we would
reject the null hypothesis.
fail to reject the null hypothesis.

Solutions

Expert Solution

Values ( X )
6.72 0.1045
5.94 1.2173
8.83 3.1923
8.86 3.3004
6.38 0.44
5.36 2.8335
7.79 0.5576
7.21 0.0278
8.4 1.8406
8.09 1.0956
5.52 2.3204
5.4 2.6351
Total 84.52 19.5651




Test Statistic :-

t = 2.7098

Test Criteria :-

Reject null hypothesis if

Result :- Reject null hypothesis

P value

Looking for the value  t = 2.7098 in t table across 11 degree of freedom

t = 2.7098 lies between the values 2.201 and 2.718 respective P vlaues are 0.025 and 0.010.

Using excel to calculate P value = 0.0101

Decision based on P value

Reject null hypothesis if P value < level of significance

0.0101 < 0.05, reject null hypothesis

We would reject null hypothesis.


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