Question

Write the balanced net ionic equations

1. HC2H3O2 and KNO2 added to I-

2. Chlorine water added to Br-

3. H2SO4 and Ba(OH)2 added to CO32-

4. AgNO3 added to Cl-

5. FeSO4 and H2SO4 added to NO3-

Answer 1

1 2KI + 2KNO₂ + 4CH₃COOH = 4CH₃COOK + I₂ + 2NO + 2H₂O

I^- is taken as KI since KI splits as K⁺ and I^- ions further CH₃COOH splits as CH₃COO^- and H⁺ KNO₂ splits as NO₂^- and K⁺ and the reaction proceeds. here CH₃COOH and KNO₂ are concentrated chemicals.

2, 2NaBr (aq) + Cl₂ (aq) → 2 NaCl (aq) + Br₂ (aq)

the net ionic equation is

Cl2 (aq)+ 2 Br- (aq) → 2 Cl- (aq) + Br2 (aq) K2CO3 + H2SO4 → K2SO4 + CO2 + H2O 2K+ + CO32- + 2H+ + SO42- → K2SO4 + CO2 + H2O K2CO3 + Ba(OH)2 = 2 KOH + BaCO3​ 2K+ + CO32- + Ba2+ + 2OH- → ​ 2 KOH + BaCO3​ ​ here KOH is a strong base and BaCO3​ ​ is a salt . AgNO3 + KCl → AgCl + KNO3 here AgCl gets precipitated and KNO3 is a salt. Ag++ NO3- + K++ Cl- → ​  AgCl + KNO3 ​ 6FeSO4 + 4H2SO4 + 2KNO3 → 3Fe2(SO4)3 + 2NO + K2SO4 + 4H2O​ 6Fe2++ 8SO42- + 4H++​ ​2K+ +​ NO3- → ​ 3Fe2(SO4)3 + 2NO + K2SO4 + 4H2O​​ Iron(II) sulfate react with sulfuric acid and potassium nitrate to produce iron(III) sulfate, nitric oxide, potassium sulfate and water. Iron(II) sulfate and sulfuric acid - concentrated solutions. The reaction takes place in a boiling solution.