Question

Given a string of at least 3 characters as input, if the length of the string is odd return the character in the middle as a string. If the string is even return the two characters at the midpoint.

--------------------------------------------------------------

public class Class1 {

public static String midString(String str) {
    //Enter code here
}
}

Answer 1

Please find the Updated code for the following:

Code:

public class Class1
{
   //Defined a method which accepts a string and returns a string
   public static String midString(String str)
   {
  
       //Check if the string is an odd length
if(str.length()%2==0)
{
//Then returns the two characters at the midpoint
   return str.substring(str.length()/2-1,str.length()/2+1);
}
//Else part where the string is an even length
else
{
//Then return the character in the middle
   return str.substring(str.length()/2,str.length()/2+1);
}
  
}
   //Validating the above method
   public static void main(String[] args)
   {
       //Defined 2 strings one is of even and other is off odd length
       String EvenLengthString="ABCDEFGH";
       String oddLengthString ="RSTUVWXYZ";
       //Calling the function and then printing out the resultant string
       System.out.println(midString(EvenLengthString));
       System.out.println(midString(oddLengthString));
   }
  
}

Please check the compiled program and its output for your reference:

Output:

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