In: Statistics and Probability
A department store claims that their average customer satisfaction rating is 28.5. We believe that this is too high so we randomly sample 40 customers and find a sample average of 25.2. If the standard deviation of customer satisfaction for this store is 13.1, what is the probability of observing a sample at least this far below the claimed mean, assuming the claim is true? Can someone please help me complete this on a TI-84?
Solution:-) First let us try to understand the question, as the standard deviation of population is known and sample size is greater than 20. So, we will definitely used Z-test here. So, the information are;-
We have to find
Here are the methods for TI-84 calculator:-
1) Press STAT and the right arrow twice to select TESTS.
2) To select the highlighted:Z-Test…Press ENTER.
3) Use right arrow to select Stats(Don't SELECT DATA) (summary values rather than raw data) and Press ENTER.Use the down arrow to Enter the hypothesized mean, population standard deviation, sample mean, and sample size.Select alternate hypothesis.Press down arrow to select Calculate and press ENTER.
4) Enter the values and PRESS Calculate Draw.( note )
5) You will have z as -1.59 and corresponding p-value is 0.055917..
CHEERS!!