The standard germination rate for foxglove seeds (Digitalis) produced by a large nursery is a 70%...

The standard germination rate for foxglove seeds (Digitalis) produced by a large nursery is a 70% germination rate. Twelve samples of seeds have been stored for 1 year. When planted it is determined that their germination rate is 62% with a SEM of 8%.

What type of t-test should you use?

What is the t-value?

Would you use a one-tailed test, or a two-tailed test?

What are the degrees of freedom?

Using the table of t-values given at the end of this assignment, would you conclude that this difference was likely to have happened by change? Explain your reasoning.

Expert Solution

orchestra answered 2 years ago

Information on a large packet of seeds indicates that the germination rate is p0=92%. Some researchers...

Information on a large packet of seeds indicates that the germination rate is p0=92%. Some researchers claim that the proportion of germination should be higher than that. (a) (2 points) Based on the indication of the information, what’s the probability that more than 95% of the 300 seeds in the packet will germinate? (b) (3 points) Now a random sample containing 300 seeds with 290 germinated is chosen to test this claim. Based on the sample, construct a 90% conﬁdence...

Information on a packet of seeds claims that the germination rate is 92%. You purchase a...

Information on a packet of seeds claims that the germination rate is 92%. You purchase a packet that has 160 seeds in it.a.verify that the sample is large enough?b.Find the mean .c.Find the standard deviation . (leave as a square root)d.What’s the probability that more than 96% of the seeds in your packet in the packet will germinate? e.What is the probability that less than 90% of the seeds will germinate?

What is the effect of PH on the germination and growth of seeds

The imbibition in seeds takes place during seed germination because of The imbibition in seeds takes...

The imbibition in seeds takes place during seed germination because of The imbibition in seeds takes place during seed germination because of the loss of water due to the high water potential of the seed. the loss of water due to the low water potential of the dry seed. the uptake of water due to the low water potential of the dry seed. the uptake of water due to the high water potential of the dry seed.

A simple random sample of germination times (in days) for 7 seeds of a new strain...

A simple random sample of germination times (in days) for 7 seeds of a new strain of snap beans has a sample mean of 15.57 and standard deviation of 3.21. (a) Determine a 99% confidence interval for the true mean germination time for this strain. (b) Choose a correct interpretation to your result in part (a): i. We can be 99% sure the sample average of 7 germination times is in the interval calculated in part (a). ii. We can...

Recorded here are the germination times (in days) for sixteen randomly chosen seeds of a new...

Recorded here are the germination times (in days) for sixteen randomly chosen seeds of a new type of bean: 11, 13, 12, 13, 20, 15, 18, 17, 14, 18, 10, 12, 13, 17, 14, 17 Send data to Excel Assuming that germination times are normally distributed, find a 95% confidence interval for the mean germination time for all beans of this type. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers...

Question 10 Recorded here are the germination times (in days) for fifteen randomly chosen seeds of...

Question 10 Recorded here are the germination times (in days) for fifteen randomly chosen seeds of a new type of bean: 11, 13, 11, 10, 15, 15, 10, 20, 10, 20, 13, 21, 16, 14, 12 Assuming that germination times are normally distributed, find a 95% confidence interval for the mean germination time for all beans of this type. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal...

A biologist estimates that the chance of germination for a type of bean seed is 0.8. A student was given 10 seeds.

A biologist estimates that the chance of germination for a type of bean seed is 0.8. A student was given 10 seeds. Let Xbe the number of seeds germinated from 10 seeds. a) Assuming that the germination of seeds is independent, explain why the distribution of Xis binomial. b) What are the values of nand p? c) What is the mean and standard deviation of the number of seeds that germinate? d) What is the probability that all seeds...

To determine the possible effect of a chemical treatment on the rate of seed germination, 100...

To determine the possible effect of a chemical treatment on the rate of seed germination, 100 chemically treated seeds and 150 untreated seeds were sown. It was found that 88 of the chemically treated seeds and 126 of the untreated seeds germinated. Is there a difference in the proportions? Does the chemical trim in effect seed germination?

A type of tomato seed has a germination rate of 91%. A random sample of 160...

A type of tomato seed has a germination rate of 91%. A random sample of 160 of these tomato seeds is selected. What is the probability that more than 85% of this sample will germinate? a) 0.8023 b) 0.9834 c) 0.0040 d) 0.9960

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