In: Chemistry
Calculate the pH of 0.100 L of the buffer 0.110 M CH3COONa/0.130 M CH3COOH before and after the addition of the following species. (Assume there is no change in volume.)
(a) pH of the starting buffer:
(b) pH after addition of 0.0030 mol HCl:
(c) pH after addition of 0.0040 mol NaOH (added to a fresh solution of the starting buffer):
no of moles of CH3COONa = molarity * volume in L
= 0.11*0.1 = 0.011moles
no of moles of CH3COOH = molarity * volume in L
= 0.13*0.1 = 0.013 moles
PKa = 4.75 for CH3COOH
PH = PKa + log[CH3COONa]/[CH3COOH]
= 4.75+
log0.011/0.013
= 4.75-0.0725 =
4.6775
b. no of moles of CH3COONa after addition of 0.003 moles of HCl =
0.011-0.003 = 0.008mole
no of moles of CH3COOH after addtion of 0.003 moles of
HCl = 0.013+ 0.003 = 0.016moles
PH = Pka + log[CH3COONa]/[CH3COOH]
= 4.75+ log0.008/0.016
= 4.75-0.3010 = 4.449
c. no of moles of CH3COONa after addition of 0.004 moles of NaOH =
0.011+0.004 = 0.015mole
no of moles of CH3COOH after addtion of 0.004 moles of
NaOH = 0.013- 0.004 = 0.009moles
PH = Pka + log[CH3COONa]/[CH3COOH]
= 4.75+ log0.015/0.009
= 4.75+0.2218 = 4.9718