Question

In: Biology

The height of a type of bean plants is determined by five unlinked genes called A,...

The height of a type of bean plants is determined by five unlinked genes called A, B, C, D, and E. Each gene has two alleles: additive (uppercase letter) and nonadditive (lowercase letter).

How many phenotypic classes would you expect?

The shortest plants are 130 cm. The tallest plants are 220 cm. Estimate how many centimeters each allele contributes to the height difference.

The genotypes are known for two bean plants. Plant 1 is genotype AABbccDdEE. Plant 2 is genotype aaBBCcDdEE. What are their heights?

If the two plants from above are crossed, what is the probability they will produce a plant that is taller than either parent?

Solutions

Expert Solution

phenotypic classes would be expected = 11 (all allele A,B,C,D,E have same effect on plant height and a, b, c, d, e have same effect we can make total 11 cases so total 11 classes would be expected.

shortest plant = 130 cm

Genotype of the shortest plant = aabbccddee

height contributed by each allele = 130/10 = 13 cm (total number of allele present =10)

Tallest plant =220 cm

Genotype of the tallest plant = AABBCCDDEE

height contributed by each allele = 220/10 =22 cm (total number of allele present =10)

height of AABbccDdEE genotype = (22+22)+(22+13)+(13+13)+(22+13)+(22+22) = 184

height of aaBBCcDdEE genotype = (13+13)+(22+22)+(22+13)+(22+13)+(22+22) = 184

probability they will produce a plant that is taller than either parent

the plant are taller than their parent only if they have following genotype

1. AABBCcDDEE

2.AABbCcDDEE

3. AABBCcDdEE=

(AA and EE has no effect on probability as they are same in all progeny plant)

BB x Bb = 2 BB and 2Bb = probability of each genotype = 2/4

cc x Cc = 2 cc and 2Cc= probability of each genotype = 2/4

Dd x Dd = 1 DD: 2 Dd : 1 dd

probabibilty of DD = 1/4, probabibilty of dd = 1/4, probabibilty of Dd = 1/4,

probabibilty of AABBCcDDEE genotype = probabibilty of BB x probabibilty of Cc x probabibilty of DD =2/4 x 2/4 x 1/4 = 4/64

probabibilty of AABbCcDDEE genotype = probabibilty of Bb x probabibilty of Cc x probabibilty of DD =2/4 x 2/4 x 1/4 = 4/64

probabibilty of AABBCcDdEE genotype = probabibilty of BB x probabibilty of Cc x probabibilty of Dd =2/4 x 2/4 x 2/4 = 8/64

probability they will produce a plant that is taller than either parent = probabibilty of AABBCcDDEE genotype + probabibilty of AABbCcDDEE genotype + probabibilty of AABBCcDdEE genotype

4/64 + 4/64 + 8/64 =16/64 = 1/4 = 0.25

gladiator answered 3 months ago

Next > < Previous

Related Solutions

1. Assume alleles of the height gene of corn plants determine the height of the plant's...

1. Assume alleles of the height gene of corn plants determine the height of the plant's stalks, and that there are two alleles of the gene: "H1" and "H2." Individuals that are homozygous for the "H1" allele are 10 feet in height, individuals that are homozygous for the "H2" allele are 6 feet in height, and heterozygotes for these two alleles are 6 feet in height. From this data, it can be concluded that, with respect to the "H1" allele,...

A new fertilizer was applied to the soil of 283 bean plants. 21% showed increased growth....

A new fertilizer was applied to the soil of 283 bean plants. 21% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): _______ Confidence Interval: _______% to _______%

The height of plants is normally distributed with a mean of 32 inches and a standard...

The height of plants is normally distributed with a mean of 32 inches and a standard deviation of 8 inches. What is the probability that the average height of a sample of 25 plants is greater than 30 inches

Most plants are what are called C3 plants. They have not evolved mechanisms to avoid photorespiration....

Most plants are what are called C3 plants. They have not evolved mechanisms to avoid photorespiration. C4 and CAM plants have mechanisms to decrease the likelihood of photorespiration occuring. Briefly describe how each type of plants avoids photorespiration.

Create a class called Height Copy the code for Height given below into the class. Remember...

Create a class called Height Copy the code for Height given below into the class. Remember – test the methods as you go Take a few minutes to understand what the class does. There are comments where you will have to be changing code. A list of changes are given Change the setFeet and setInches mutators to make sure the height and width will not be less than 0, no matter what is passed in to it Change constructor that...

A researcher collected data on the height (cm) of eight legume plants and the number of...

A researcher collected data on the height (cm) of eight legume plants and the number of flowers on the plant one week after flowering began. Height (x) 24 26 28 30 32 34 37 39 Number of Flowers (y) 15 21 17 16 20 14 11 19 SUMMARY OUTPUT Regression Statistics Multiple R 0.247 R Square 0.061 Adjusted R Square -0.096 Standard Error 3.492 Observations 8 ANOVA df SS MS F Significance F Regression 1 4.73 4.73 0.388 0.556 Residual...

10. A woman with average height, and type A- blood, and a man with type B+...

10. A woman with average height, and type A- blood, and a man with type B+ blood and achondroplastic dwarfism, have a daughter with type O- blood, average height and cystic fibrosis. What are the genes found in the gamete the father produced that led to the child? Start with ABO, Rh, height, cystic fibrosis, and sex. (Separate each gene by a comma, e.g. the gamete produced by a blue-eyed, hairless knuckled person would contain b, kn). Answer: 11.A woman...

A woman with average height, and type A- blood, and a man with type B+ blood...

A woman with average height, and type A- blood, and a man with type B+ blood and achondroplastic dwarfism, have a daughter with type O- blood, average height and cystic fibrosis. What is the probability of this couple producing this child? Select one: a. 1/128 b. 1/16 c. 1/8 d. 1/64 e. 1/32 A woman with average height, and type A- blood, and a man with type B+ blood and achondroplastic dwarfism, have a daughter with type O- blood, average...

A woman with average height, and type A- blood, and a man with type B+ blood...

A woman with average height, and type A- blood, and a man with type B+ blood and achondroplastic dwarfism, have a daughter with type O- blood, average height and cystic fibrosis. Write the genotype of the mother, starting with ABO, Rh, height, cystic fibrosis, and sex. Be sure to follow the nomenclature rules. (For example: for a blue-eyed person with hairless knuckles, you would write b/b, kn/kn. For a brown-eyed person with hairy knuckles, write B/B, Kn/Kn, if the person...

In a specific population of plants the occurrence of homozygous recessive (aa) individuals is determined to...

In a specific population of plants the occurrence of homozygous recessive (aa) individuals is determined to be 9%. Assume the population is in Hardy-Weinberg Equilibrium. What is the frequency of the dominant (A) allele in the population? 0.9 0.7 0.3 0.09 What is the frequency of the recessive (a) allele in the population? 0.9 0.7 0.3 0.09 What is the frequency of the homozygous dominant individuals in the population? 0.810 0.490 0.900 0.081 What is the frequency of the heterozygotes...

Subjects