Question

1. Write a user-defined function named printBox that, when called, will output the following sequence of characters:

OOOOOOOO

OOOOOOOO

OO            OO

OO            OO

OOOOOOOO

OOOOOOOO

2. Write a user-defined function named printArrow that, when called, will accept an integer called arrowSize and will output a sequence of *’s such that there are arrowSize number of rows with the number of * incrementing, and then arrowSize-1 rows with the number of * decrementing:
   1. If arrowSize = 3, then the output is:

*

**

***

**

*

2. If the arrowSize = 5, then the output is:

*

**

***

****

*****

****

***

**

*

And so on…

(Hint: you will need two for-loops in a for-loop)

Answer 1

import java.util.*;
public class Solution {
// printBox method
   static void printBox() {
       for(int i=0; i<6; i++) {
           for(int j=0; j<8; j++) {
               if((i==2 && j>1 && j<6) || (i==3 && j>1 && j<6)) // Check the condition

System.out.print(" ");
               else

System.out.print(" O ");
           }
           System.out.println(); // For enter the new line.
       }
   }
// printArrow method taking arrowSize as a parameter
   static void printArrow(int arrowSize) {
       int i=0, j=0, k=0, l=1;
       for(i=0; i<arrowSize*2; i++) { // Outer loop
           if(i<=arrowSize) {
               for(j=0; j<i; j++) { // Inner loop
                   System.out.print("* ");
               }
               System.out.println();
           }else {
               for(k=0; k<arrowSize-l; k++) { // Inner loop
                   System.out.print("* ");
               }
               l++;
               System.out.println(); // For enter the new line.
           }
       }
      
   }

   public static void main(String[] args) {
       Scanner scan = new Scanner(System.in);
       printBox(); // Call the printBox method.
       printArrow(scan.nextInt()); // Call the printArrow method.
       printArrow(scan.nextInt()); // Call the printArrow method.

   }

}

Output :