In: Statistics and Probability
Once you have the dataset, please use knowledge gained in other business and/or economics classes to realize what topic and theory the data could relate and a research question that it could allow you to answer. More specifically, please put together an analysis by making sure your project report includes the following:
7.1. Specify the level of significance (Type I error associated with the null hypothesis),
7.2. Determine the test statistic (the appropriate statistical test as mentioned under point 5 above),
7.3. Determine the critical values (and region(s) if applicable),
DATA :
Production costs in company 1 | Production costs in company 2 |
1,30 | 6,50 |
2,50 | 8,70 |
2,30 | 9,80 |
8,10 | 10,20 |
5,00 | 7,90 |
7,00 | 6,50 |
7,50 | 8,70 |
5,20 | 7,90 |
4,40 | 8,70 |
7,60 | 9,10 |
9,00 | 8,40 |
7,60 | 6,40 |
4,50 | 7,20 |
1,10 | 5,80 |
5,60 | 6,90 |
6,20 | 5,90 |
7,00 | 7,60 |
6,90 | 7,80 |
5,60 | 7,30 |
5,20 | 4,60 |
7,20 | 8,00 |
5,00 | 7,10 |
8,50 | 8,90 |
7,80 | 8,90 |
8,80 | 9,30 |
4,20 | 5,40 |
3,40 | 3,40 |
5,80 | 5,90 |
7,80 | 9,90 |
9,90 | 11,90 |
1) in this case, a 95% confidence level is considered and hence the Type 1 error = 0.05 or 5%.
2) Here, one factor Anova will be used to determine whether there is a significant difference in the average production cost of both the companies...
3) Analysis:
The output of one factor Anova is shown below:
Hypothesis:
H0: U1 = U2 (Null Hypothesis)
Ha: All the means are not equal (Alternate Hypothesis)
Here, the critical F value = 4.006
As the P value in this experiment is 0.0016, which is less than 0.05, so in this case, the alternate hypothesis is accepted. This means that there is a significant difference observed in the average production cost for both the companies...
End of the Solution