Consider a manufacturing process that produces cylindrical component parts for the automotive industry. According to specifications, it is important that the process produces parts having a mean diameter of 5.0 millimeters. An experiment is conducted in which 100 parts produced by the process are selected randomly and the diameter measured on each part. It is known that the population standard deviation is 0.1. It was found that the sample mean diameter is 5.027 millimeters. The process engineer Mr. Tan would like to find out how likely is it that one could obtain a sample mean diameter of at least 5.027 with sample size n = 100, if the population mean µ = 5.0. Apply the concept of central limit theorem. Mr Tan claimed that “In only 7 in 1000 experiments, one would experience by chance a sample mean that deviates from the population mean by as much as 0.027.” Do you agree? Explain your reasoning.

M3 Discussion: The Respiratory System

This is something of a different type of discussion. Discuss in 1-2 short paragraphs 2 of the most informative pieces of information you learned in this chapter. You can discuss one of the homeostatic imbalances, a fundamental principle of respiratory capacities, gas exchange, etc, anything that was presented in the chapter you particuarly are interested in.

Two firms, A and B, sell widgets to a market of 100 buyers. The firms' widgets are undifferentiated, and the firms know each others' costs and capacities. Furthermore the firms are playing a one-time pricing game; widgets are obsolete after this one selling opportunity. Each buyer is interested in purchasing a single widget, and has an RP of $10.

Firm A has lower costs than Firm B, but also has lower capacity. Specifically, their (constant) marginal costs and capacities are as follows.

   Finally, assume that each firm can only post prices in whole dollar amounts. (This question is motivated by firms selling through coin-operated vending machines. It is too costly to stock such machines with pennies, so sellers must set prices in fixed increments of larger denomination coins.) Throughout this entire problem, firms may only choose prices of $1.00, $2.00, $3.00, ..., up to $10.00. Firms may NOT use prices such as $1.50, $2.99, $3.83, etc.

(2a.) Find equilibrium prices for this one-time pricing game. (As usual: all buyers go to the firm with the lowest price. However if Firm A's price is no higher than Firm B's price, Firm A serves only 30 buyers, and the rest go to Firm B. Your answer should be a pair of prices, one for each firm.)

(2b.) Suppose that before the pricing game starts, Firm A can build a production plant that would have full capacity of 100 units. (Marginal costs would remain the same, and Firm B would see Firm A's new capacity. Then firms would simultaneously set some equilibrium prices.)

Ignoring the cost of building, how much profit would Firm A earn if it expanded?  Firm A would now earn profits of ______________. (You must show your calculations for credit. The same assumptions apply as the previous part, except now the firms split the market 50/50 if they price equally.)

Classify the following transactions (current account transaction, financial account transaction), the sign of entry (plus or minus/ debit or credit). Choose one country of reference.

a) Walmart issues a corporate bond in the UK

b) A German tourist rents a car in Iceland

c) A U.S. worker in Canada wires money back to his family in the U.S.

d) A French company builds a plant in South Africa

e) Toyota exports cars to Spain.

Describe what happens when you try to push a heavy box (> 200lbs) that has been sitting on the floor for some time a) before it starts to move b) right after it starts to move c) if it acquired an acceleration without you pushing it harder, explain why in details using static and kinetic forces of frictions and 2nd Newton

It takes two materials to produce our widgets, Material X and Material Y. All of Material X is added at the beginning of processing, and all of Material Y is added at the 30% point in processing. At the beginning of March, there were 8000 units in Work in Process, 20% complete as to processing (Conversion). During March, there were 30000 units started into the process. At the end of March, there were 5000 units in Work in Process, 70% complete as to processing, Our Company uses the FIFO method of process costing. Prepare an equivalent units chart for the month of March

In April, we started 40000 units and completed 39000 units. The ending Work in process for April was 10% complete as to processing. Prepare an equivalent units chart for April.

During a review of financial statements, an accountant decides to emphasize a matter in the review report. Which of the following is an example of a matter that the accountant would most likely want to emphasize?

Question 4 options:

A) The entity has had significant tax expenses as a result of a new tax law.

B) Other entities in the same industry have recently changed from LIFO to FIFO.

C) The IRS has notified the entity that it intends to audit income tax returns for prior years.

D) The entity has had significant transactions with related parties.

. Write an essay of not less than 3 pages on only one topic chosen from any of the following areas in introduction to computing:

1. basic concepts of word processing
2. Internet application
3. computer systems
4. ergonomics - health implications in the use of a PC
5. protection and care of a computer system

Okay for this question, I obviously don't need a quantity because I dont have any, but how would I approach this question in lab if asked:

"Quantify the scatter (or range) of the three resistance values as a percent of their averages"

I don't know what my answer should look like or what I'm supposed to do with the resistance values

Hello, Im trying to converter this C# program into python, i have started but am stuck on alot of small syntax! Please help me!

def Wired
def "RTClib.h"

int PWMSTEP = 2
int PWMSTART = 340
int PWMEND = 1023
int iENDPOINT
int correctionStep = 1
int correctionThreshold = 5
int fadeOutstep = 5

int numReadings = 5
float readings[numReadings]
int readIndex = 0
float total = 0
float average = 0

def SoftwareSerialmySerial = 7 8

Adafruit_RGBLCDShield lcd = Adafruit_RGBLCDShield();

def RED 0x1
def YELLOW 0x3
def GREEN 0x2
def TEAL 0x6
def BLUE 0x4
def VIOLET 0x5
def WHITE 0x7
int sensorPin = A1
int sensorPin2 = A2
int sensorValue = 0
int sensor2Value = 0

int isetPWM = 0
int usersetMaxFlow = 0
int usersetMinFlow = 0
int setFlow = 0
float fymin
bool DBUG = true

int rawflow = 0
int rawpressure = 0

def sflowrate
int flowrate = 0
int ipwm = 0
int oldipwm = 0
float flowdifference
int actualflowrate = 0
int actualpressure = 0
bool bnewGasIn

bool bovershoot = false
int imode

int led = LED_BUILTIN
int PWMPIN = 10

int PRESSUREPIN = A6

int RESET = 1
int SYSTEM_IDLE = 6
int GASIN = 2
int FADEIN = 13
int FADEOUT = 14
int RAWGASIN = 15
int STEP1 = 100
int STEP0 = 10
int STEP2 = 200
int STEP3 = 300
int STEP4 = 400
int STEP5 = 500

int MMIN = 16
int MMAX = 17
int MRUN = 18

int SYSTEM_STATE
int TEST_STATE

bool FLOW_MODE = true
float newpflow
def previousMillis = 0
int initialflowrate
def interval = 0
int hbcounter = 0
int buttonState = 0
def buf[20]
int incomingLen
int sblen
def c
bool bOkNum
float ymin
float ymax
float xmax
int pressureOffset
int targetpressure
int zeropressure
def startMillis
int address = 0
str flowDataStruct {
int deltaP[51]
int zeropressure;
}
int tdeltaP[51]
def DataStructflowData[3]
int itarget
int iindex
int ncages

void setup() {

int iret = EEPROM.readBlock(address, flowData,3)

def SYSTEM_STATE = SYSTEM_IDLE
def Timer1.initialize(1000); // msec so 2500=400Hz
def pinMode(PWMPIN, OUTPUT);

def Serial.begin(9600);
def mySerial.begin(9600);
for (int thisReading = 0; thisReading < numReadings; thisReading++) {
readings[thisReading] = 0;
}
EEPROM.readBlock(address, flowData,3);
print "Prodigy Calibration"
}

void loop() {

if (Serial.available()) {
c = Serial.read();
print "incoming char: "
// println(c);
if (c==63)
{
print "Prodigy Calibration 001"
print "1,2,3 to start"
print "W to save to eeprom"
print "any char to abort"
} else

if ((c==87)||(c==119))
{
print "Calibration data"
print "one cage: zeroPressure=");
print flowData[0].zeropressure
print flowData[0].deltaP[0]);
for (int i=1;i<51;i++)
{
print ","
print flowData[0].deltaP[i]
}
print " "
print "two cages: zeroPressure="
print (flowData[1].zeropressure)
print (flowData[1].deltaP[0])
for (int i=0;i<51;i++)
{
print ","
print (flowData[1].deltaP[i])
}
print " "
print "three cages: zeroPressure="
Serial.println(flowData[2].zeropressure);
Serial.print( flowData[2].deltaP[0]);
for (int i=0;i<51;i++)
{
print ","
print flowData[2].deltaP[i]
print " "
int iret = EEPROM.writeBlock(address, flowData,3);
print "Saved."

} else

if (c == 49)
{
for (int i=0;i<51;i++)
{
def tdeltaP[i] = 0;
}
def itarget = 50;
def iindex = 0;
def iENDPOINT = 1000;
def ipwm = 0; //start pwm
def Timer1.pwm(PWMPIN, ipwm);
print "Starting one cage calibration."
def SYSTEM_STATE = GASIN;
def TEST_STATE = STEP0;
def ncages = 0;
zeropressure = analogRead(PRESSUREPIN);
flowData[ncages].zeropressure = zeropressure;
} else
if (c == 50)
{
for (int i=0;i<51;i++)
{
tdeltaP[i] = 0;
}
itarget = 50;
iindex = 0;
iENDPOINT = 650;
ipwm = 0; //start pwm
Timer1.pwm(PWMPIN, ipwm);
print "Starting two cage calibration."
SYSTEM_STATE = GASIN;
TEST_STATE = STEP0;
ncages = 1;
zeropressure = analogRead(PRESSUREPIN);
flowData[ncages].zeropressure = zeropressure;

} else
if (c == 51)
{
zeropressure = analogRead(PRESSUREPIN);
for (int i=0;i<51;i++)
{
tdeltaP[i] = 0;
}
itarget = 50;
iindex = 0;
iENDPOINT = 425;
ipwm = 0; //start pwm
Timer1.pwm(PWMPIN, ipwm);
print "Starting three cage calibration."
SYSTEM_STATE = GASIN;
TEST_STATE = STEP0;
ncages = 2;
zeropressure = analogRead(PRESSUREPIN);
flowData[ncages].zeropressure = zeropressure;

} else
{
print "Stopping."
SYSTEM_STATE = FADEOUT;
}
}

long currentMillis = millis();
long ltemp = (unsigned long) (currentMillis - previousMillis);
float flowdifference = (float)setFlow - (newpflow*10.0);

float tp;
int itemp;
if (SYSTEM_STATE==FADEOUT)
{
while (1) {
if (ipwm < 250)
ipwm -= 10;
else
if (ipwm > 500)
ipwm -= fadeOutstep*2;
else
ipwm -= 10;
if (ipwm<=0)
{
ipwm=0;
Timer1.pwm(PWMPIN, ipwm); //10bit
SYSTEM_STATE=SYSTEM_IDLE;
break;

}
Timer1.pwm(PWMPIN, ipwm); //10bit
}

} else
if (SYSTEM_STATE==GASIN)
{
switch (TEST_STATE)
{
// set PWM
case STEP0:
tp = analogRead(PRESSUREPIN);
total = 0;
// tp = ((float)tp*(float)5.0)/(float)1023.0;
for (int thisReading = 0; thisReading < numReadings; thisReading++) {
readings[thisReading] = tp;
total+=tp;
}
// itemp = (int)((total / numReadings)*1000.0);
itemp = (int)((total / numReadings));
print "Start initial p = "
print itemp
readIndex = 0;
startMillis = millis();
TEST_STATE = STEP1;
break;
// set zero offset
case STEP1:
tp = analogRead(PRESSUREPIN);
// tp = ((float)tp*(float)5.0)/(float)1023.0;
print "actualpressure="
print tp

total = total - readings[readIndex];
readings[readIndex] = tp;
total = total + readings[readIndex];
readIndex = readIndex + 1;
if (readIndex >= numReadings) {
readIndex = 0;
}
zeropressure = (int)((total / numReadings));
// zeropressure = (int)((total / numReadings)*1000.0);
print " p0="
print zeropressure
if (((unsigned long) (currentMillis - startMillis))>3000)
{
TEST_STATE = STEP2;
ipwm = PWMSTART;
Timer1.pwm(PWMPIN, ipwm); //10bit
startMillis = millis();
}
break;

// set PWM
case STEP2:
tp = analogRead(PRESSUREPIN);
// tp = ((float)tp*(float)5.0)/(float)1023.0;

total = total - readings[readIndex];
readings[readIndex] = tp;
total = total + readings[readIndex];
readIndex = readIndex + 1;
if (readIndex >= numReadings) {
readIndex = 0;
}
actualpressure = (int)((total / numReadings)*1000.0);
// actualpressure = (int)((tp)*1000.0);
actualpressure = (int)((tp));
if (((unsigned long) (currentMillis - startMillis))>7000) //10000)
{

print "zp="
print zeropressure
print " pressure="
print ","
print actualpressure
print " pwm="
print ","
print ipwm
// tp = analogRead(A5);
// tp = ((float)tp*(float)5.0)/(float)1023.0;
//// Serial.print( " Fv=");
print ","
mySerial.write('F');
mySerial.write('\r');
delay(500);

incomingLen = mySerial.available();
if (incomingLen > 0) {
// Serial.println(" ");
print "newchar: incomingLen="
print incomingLen
print "-"
sblen=0;
bOkNum = false;
bool bcont = true;
for (int i=0;i<incomingLen;i++)
{
c = mySerial.read();
if (c==13)
{
bcont = false;
bOkNum = true;
buf[sblen++]=0;
// break;
} else
if (bcont)
{
buf[sblen++]=c;
print "-"
print c
}

}
// Serial.println("#");
if (bOkNum)
{
Str stemp = String((char *) buf);
tp = stemp.toFloat();
print " flow="
print tp
print "#"
} else tp = -1.00;

print tp
int itemp1 = (int)(tp*100.0);
if (itemp1 >= itarget)
{

print "target found: target="
print itarget
print " deltaP="
print actualpressure
tdeltaP[iindex++] = actualpressure;
if (itarget==iENDPOINT)
{
SYSTEM_STATE=FADEOUT;
print ""
print "Completed. Array is"

for (int i=0;i<51;i++)
{
flowData[ncages].deltaP[i]=tdeltaP[i];
print tdeltaP[i]
print ","
}
print " "

}
itarget+=25;

}
}
// if (((long) (currentMillis - startMillis))>1500)
// {
if (itarget>=600)
PWMSTEP=5;
else
PWMSTEP=2;
ipwm+=PWMSTEP;
if (ipwm > PWMEND){ //changed from 255 for 10bit
SYSTEM_STATE=FADEOUT;
print ""
print "Completed. Array is"

for (int i=0;i<51;i++)
{
flowData[ncages].deltaP[i]=tdeltaP[i];
print tdeltaP[i]
print ","
}
print " "
}
Timer1.pwm(PWMPIN, ipwm); //10bit
startMillis = millis();
}
break;

}

}

}

Problem 10-4A Sell or process LO A1

Harold Manufacturing produces denim clothing. This year, it produced 5,120 denim jackets at a manufacturing cost of $42.00 each. These jackets were damaged in the warehouse during storage. Management investigated the matter and identified three alternatives for these jackets.

1. Jackets can be sold to a secondhand clothing shop for $8.00 each.
2. Jackets can be disassembled at a cost of $31,300 and sold to a recycler for $11.00 each.
3. Jackets can be reworked and turned into good jackets. However, with the damage, management estimates it will be able to assemble the good parts of the 5,120 jackets into only 2,980 jackets. The remaining pieces of fabric will be discarded. The cost of reworking the jackets will be $101,800, but the jackets can then be sold for their regular price of $45.00 each.

Required:
1. Calculate the incremental income.

For this discussion you will need to select a product, good, or service that you purchase on a regular basis. This could be anything from your morning coffee to the make of your car to your favorite chain restaurant. Conduct some formal research on the marketing strategy of the company or brand before you start your posts.

For Discussion

• Name of product and company: Use the proper corporate name, not a nickname.. Include pictures if you’re handy with uploading/inserting images.
• Product description: Briefly describe the product you’ve selected along with any relevant history that led you to choose this product/brand.
• Describe the key marketing strategies of your selected product. You should base your evaluation and report on what you can observe about how the four Ps are applied to the product you chose.
  • Product: Describe the want or need your product addresses.
  • Placement: Describe the physical location of the product among its closest competitors (a quick picture of the shelf would tell a good story!), and describe what this placement says about the marketing strategy.
  • Pricing: Describe the pricing strategy. A good description would include observations about the closest competitive product and its relative pricing.
  • Promotion: Describe how the product is being promoted. You could include any obvious physical/in-store promotions seen on the shelf, as well as flyers, coupons, social media, online advertising, etc.
  • Other factors: You might notice other important factors about your product that lie outside the four Ps. You can include them in your report here. One example might be a unique distribution system for your product.

Required information Use the following information to answer questions [The following information applies to the questions displayed below.] The following information is available for Lock-Tite Company, which produces special-order security products and uses a job order costing system. April 30 May 31 Inventories Raw materials $ 45,000 $ 41,000 Work in process 9,200 19,700 Finished goods 61,000 33,900 Activities and information for May Raw materials purchases (paid with cash) 170,000 Factory payroll (paid with cash) 200,000 Factory overhead Indirect materials 17,000 Indirect labor 46,000 Other overhead costs 103,000 Sales (received in cash) 1,400,000 Predetermined overhead rate based on direct labor cost 55 % Exercise 15-7 Cost flows in a job order costing system LO P1, P2, P3, P4 Compute the following amounts for the month of May using T-accounts. Cost of direct materials used. Cost of direct labor used. Cost of goods manufactured. Cost of goods sold.* Gross profit. Overapplied or underapplied overhead. *Do not consider any underapplied or overapplied overhead.

A beam of sound waves of a specific frequency and intensity is passed from one medium into another, arriving at the interface at an angle that is not perpendicular to the interface. Identify TWO aspects of this sound wave that will be different about this beam now that it is travelling in the second medium compared to when it was in the first medium. Explain your answer.