Questions
A study found that the mean amount of time cars spent in​ drive-throughs of a certain​...

A study found that the mean amount of time cars spent in​ drive-throughs of a certain​ fast-food restaurant was

157.6157.6

seconds. Assuming​ drive-through times are normally distributed with a standard deviation of

3434

​seconds, complete parts​ (a) through​ (d) below.Click here to view the standard normal distribution table (page 1).

LOADING...

Click here to view the standard normal distribution table (page 2).

LOADING...

​(a) What is the probability that a randomly selected car will get through the​ restaurant's drive-through in less than

118118

​seconds?The probability that a randomly selected car will get through the​ restaurant's drive-through in less than

118118

seconds is

nothing.

​(Round to four decimal places as​ needed.)

​(b) What is the probability that a randomly selected car will spend more than

210210

seconds in the​ restaurant's drive-through?The probability that a randomly selected car will spend more than

210210

seconds in the​ restaurant's drive-through is

nothing.

​(Round to four decimal places as​ needed.)

​(c) What proportion of cars spend between

22

and

33

minutes in the​ restaurant's drive-through?The proportion of cars that spend between

22

and

33

minutes in the​ restaurant's drive-through is

nothing.

​(Round to four decimal places as​ needed.)

​(d) Would it be unusual for a car to spend more than

33

minutes in the​ restaurant's drive-through?​ Why?

In: Math

Many studies have suggested that there is a link between exercise and healthy bones. Exercise stresses...

Many studies have suggested that there is a link between exercise and healthy bones. Exercise stresses the bones and this causes them to get stronger. One study examined the effect of jumping on the bone density of growing rats. There were three treatments: a control with no jumping, a low-jump condition (the jump height was 30 centimeters), and a high-jump condition (60 centimeters). After 8 weeks of 10 jumps per day, 5 days per week, the bone density of the rats (expressed in mg/cm3 ) was measured. Here are the data. data190.dat

(a) Make a table giving the sample size, mean, and standard deviation for each group of rats. Consider whether or not it is reasonable to pool the variances. (Round your answers for x, s, and s_(x^^\_) to one decimal place.)

Group n x^^\_ s s_(x^^\_)

Control

Low jump

High jump

(b) Run the analysis of variance. Report the F statistic with its degrees of freedom and P-value. What do you conclude? (Round your test statistic to two decimal places and your P-value to three decimal places.)

F =

P =

Conclusion: There is statistically no/a significant difference between the three treatment means at the α = .05 level.

obs     group   g       density
1       Control 1       616
2       Control 1       613
3       Control 1       609
4       Control 1       619
5       Control 1       664
6       Control 1       602
7       Control 1       571
8       Control 1       585
9       Control 1       600
10      Control 1       609
11      Lowjump 2       623
12      Lowjump 2       620
13      Lowjump 2       622
14      Lowjump 2       653
15      Lowjump 2       622
16      Lowjump 2       634
17      Lowjump 2       647
18      Lowjump 2       636
19      Lowjump 2       642
20      Lowjump 2       660
21      Highjump        3       639
22      Highjump        3       611
23      Highjump        3       586
24      Highjump        3       622
25      Highjump        3       610
26      Highjump        3       605
27      Highjump        3       626
28      Highjump        3       630
29      Highjump        3       605
30      Highjump        3       640

In: Math

According to the National Eye Institute, 8% of men are red-green colorblind. A sample of 125...

According to the National Eye Institute, 8% of men are red-green colorblind. A sample of 125 men is gathered from a particular subpopulation, and 13 men in this sample are colorblind.(Without using z-value)

a. Is this statistically significant evidence that the proportion of red-green colorblind men is greater than the subpopulation than the national average with alpha = 0.05?

b. What is the maximum number of men that could have been colorblind in this sample that would lead you to fail to reject the null hypothesis?

c. Using 8% as the probability of being colorblind, find a 95% confidence interval for the number of men in a sample of 125 who are colorblind.

In: Math

What other examples can you think of where most people have more or less than the...

What other examples can you think of where most people have more or less than the average? This is true of most things with a non-symmetric distribution (e.g., weight, math scores, marathon times) but it is nice to continue the theme of the video in terms of risk (e.g., most have below average risk of a automobile accident, death by violence, or even, say, getting a date).

In: Math

The percent of persons (ages five and older) in each state who speak a language at...

The percent of persons (ages five and older) in each state who speak a language at home other than English is approximately exponentially distributed with a mean of 8.76.

The lambda of this distribution is

The probability that the percent is larger than 3.24 is P(x ≥ 3.24) =

The probability that the percent is less than 9.79 is P(x ≤ 9.79) =

The probability that the percent is between 5.76 and 11.76 is P(5.76 ≤ x ≤ 11.76) =

In: Math

A concessions manager at the Tech versus A&M football game must decide whether to have the...

A concessions manager at the Tech versus A&M football game must decide whether to have the vendors sell sun visors or umbrellas. There is a 35% chance of rain, a 25% chance of overcast skies, and a 40% chance of sunshine, according to the weather forecast in college junction, where the game is to be held. The manager estimates that the following profits will result from each decision, given each set of weather conditions:

Decision Weather Conditions Rain 0.35 Overcast 0.25 Sunshine 0.40

Sun visors Rain $-400 Overcast $-200 Sunshine $1,500

Umbrellas Rain 2,100 Overcast 0 Sunshine -800

a. Compute the expected value for each decision and select the best one.

b. Develop the opportunity loss table and compute the expected opportunity loss for each decision.

In: Math

Clinical depression is a serious disorder that affects millions of people. Depression often leads to alcohol...

Clinical depression is a serious disorder that affects millions of people. Depression often leads to alcohol as a means of easing the pain. A Gallup survey attempted to study the relationship between depression and alcohol. A random sample of adults was drawn and after a series of question each respondent was identified as a 1 = Nondrinker, 2 = moderate drinker, 3 = heavy drinker. Additionally, each respondent was asked whether they had ever been diagnosed as clinically depressed at some time in their lives (1 = Yes, 2 = No). Is there enough evidence to conclude that alcohol and depression are related?

In: Math

A manufacturing company produces electric insulators. You define the variable of interest as the strength of...

A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators. If the insulators break when in​ use, a short circuit is likely. To test the strength of the​ insulators, you carry out destructive testing to determine how much force is required to break the insulators. You measure force by observing how many pounds are applied to the insulator before it breaks. The data shown below represent the amount of force required to break a sample of 30 insulators. Complete parts a through c below. 9 10 7 7 15 19 22 24 15 35 15 30 25 22 30 31 28 29 39 62 10 6 42 40 15 22 23 24 25 25 Construct a 99​% confidence interval for the population mean force.

In: Math

Time spent using​ e-mail per session is normally​ distributed, with mu equals μ=12 minutes and sigma...

Time spent using​ e-mail per session is normally​ distributed, with mu equals μ=12 minutes and sigma equals σ=3 minutes. Assume that the time spent per session is normally distributed. Complete parts​ (a) through​ (d). b) If you select a random sample of 50 ​sessions, what is the probability that the sample mean is between 11.5 and 12 ​minutes?

In: Math

What’s the probability of getting no heads after flipping a fair coin 10 times? What’s the...

What’s the probability of getting no heads after flipping a fair coin 10 times? What’s the probability of getting no 3’s after rolling a fair 6-sided die 9 times? What’s the probability of getting a 4 at least once after rolling a fair 4-sided die 5 times? What’s the probability of getting a 5 exactly once after rolling a fair 8-sided die 7 times?

In: Math

Use the given degree of confidence and sample data to find a confidence interval for the...

Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Weights of men: 90% confidence; n = 14, = 155.7 lb, s = 13.6 lb

A. 11.0 lb < σ < 2.7 lb

B. 10.1 lb < σ < 19.1 lb

C. 10.4 lb < σ < 20.2 lb

D. 10.7 lb < σ < 17.6 lb

In: Math

Describe a scenario where a researcher could use a Goodness of Fit Test to answer a...

Describe a scenario where a researcher could use a Goodness of Fit Test to answer a research question. Fully describe the scenario and the variables involved and explain the rationale for your answer. Why is that test appropriate to use? (3 points)

Describe a scenario where a researcher could use a Test for Independence to answer a research question. Fully describe the scenario and the variables involved and explain the rationale for your answer. Why is that test appropriate to use? (3 points)

The Goodness of Fit Test and Test for Independence both use the same formula to calculate chi-square. Why? I.e., explain the logic of the test. (3 points)

Compare the Goodness of Fit Test and the Test for Independence in terms of the number of variables and levels of those that can be compared. In what ways are they similar or different? (3 points)

Describe how the Test for Independence and correlation are similar yet different. (3 points)

In: Math

It is thought that basketball teams that make too many fouls in a game tend to...

It is thought that basketball teams that make too many fouls in a game tend to lose the game even if they otherwise play well. Let x be the number of fouls more than (i.e., over and above) the opposing team. Let y be the percentage of times the team with the larger number of fouls wins the game.

x

1

4

5

6

y

51

42

33

26

Complete parts (a) through (e), given Σx = 16, Σy = 152, Σx2 = 78, Σy2 = 6130, Σxy = 540, and

r ≈ −0.966.

(a) Draw a scatter diagram displaying the data.


(b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.)

Σx =

Σy =

Σx2 =

Σy2 =

Σxy =

r =


(c) Find x, and y. Then find the equation of the least-squares line = a + bx. (Round your answers for x and y to two decimal places. Round your answers for a and b to three decimal places.)

x

=

y

=

=

+ x

(d) Graph the least-squares line. Be sure to plot the point (x, y) as a point on the line.

(e) Find the value of the coefficient of determination r2. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r2 to three decimal places. Round your answers for the percentages to one decimal place.)

r2 =

explained    

%

unexplained    

%


(f) If a team had x = 3 fouls over and above the opposing team, what does the least-squares equation forecast for y? (Round your answer to two decimal places.)
%

In: Math

Assuming the population is normally distributed, construct a 95% confidence interval for the population mean, based...

Assuming the population is normally distributed, construct a 95% confidence interval for the population mean, based on the following sample of size n = 7:

1 2 3 4 5 6 7

The mean is 4 and Standard Deviation 2.16

1. What is the lower boundary of the interval to two decimal places?

2. What is upper boundary of the interval to two decimal.

In: Math

The height of females in the United States follows a normal distribution with a mean of...

The height of females in the United States follows a normal distribution with a mean of 65 inches and a standard deviation of 2 inches.
What height marks the median?

In: Math