Questions
bag contains 7 red marbles, 5 white marbles, and 8 blue marbles. You draw 5 marbles...

bag contains 7 red marbles, 5 white marbles, and 8 blue marbles. You draw 5 marbles out at random, without replacement. What is the probability that all the marbles are red?

The probability that all the marbles are red is  .

What is the probability that exactly two of the marbles are red?


What is the probability that none of the marbles are red?

In: Math

Bayesian analysis is a probabilistic classification method based on Bayes' theorem (postulated by an English Mathematician...

Bayesian analysis is a probabilistic classification method based on Bayes' theorem

(postulated by an English Mathematician named Thomas Bayes). In summary, the

Bayesian theory rests on the belief that the evidence about the true state of a given

problem can be expressed in term of the degree of understanding of the underlying

issues. That degree of understanding can in turn be expressed in terms of probability.

And based on the observation, the theorem provides the relationship between the

probabilities of two possible events and their conditional probabilities.

The formula for Bayes Theorem is given as: P(A|B) = P(B|A) * P(A)/P(B)

Question:

Discuss the reasons for using Bayesian analysis when faced with uncertainty in

making decisions.

Discussion Requirements:

How would you describe Bayesian Theorem?

Describe the assumptions of Bayesian analysis.

Provide the example of problem where one can use Bayesian analysis in Big Data Analytics.

Describe the the problems with Bayesian analysis.

In: Math

The company Dilmart has 8,000 pieces in inventory. The average dollar value of these pieces is...

The company Dilmart has 8,000 pieces in inventory. The average dollar value of these pieces is $ 10.79 with a standard deviation equal to $ 3.34. Suppose the inventory manager selected a random sample of n = 64 pieces of inventory and found a sample mean equal to $ 11.27. The probability of obtaining a sample mean of at least $ 11.27 is approximately 0.444. Select one: True False

In: Math

One possible explanation for why some birds migrate and others maintain year-round residency in a single...

One possible explanation for why some birds migrate and others maintain year-round residency in a single location is intelligence. Specifically, birds with small brains, relative to their body size, are simply not smart enough to find food during the winter and must migrate to warmer climates where food is easily available (Sol, Lefebvre, & Rodriguez-Teijeiro, 2005). Birds with bigger brains, on the other hand, are more creative and can find food even when the weather turns harsh. Following are hypothetical data similar to the actual research results. The numbers represent relative brain size for the individual birds in each sample.

Non-Migrating

Short-Distance Migrants

Long- Distance Migrants

8

5

2

11

7

4

17

16

2

23

6

14

16

16

3

Step by step process on SPSS for One-Way ANOVA

a. Use an analysis of variance with alpha .05 to determine whether there are any significant differences among the three groups of birds.

b. Compute n2, the percentage of variance explained by the differences, between groups, for these data.

In: Math

A psychologist would like to examine how the rate of presentation affects people’s ability to memorize...

A psychologist would like to examine how the rate of presentation affects people’s ability to memorize a list of words. A list of 20 words is prepared. For one group of participants the list is presented at the rate of one word every ½ second. The next group gets one word every second. The third group has one word every 2 seconds, and the fourth group has one word every 3 seconds. After the list is presented, the psychologist asks each person to recall the entire list. The dependent variable is the number of errors in recall. The data from this experiment are as follows:

½ Second

1 Second

2 Seconds

3 Seconds

4

0

3

0

6

2

1

2

2

2

2

1

4

0

2

1

Step by step on SPSS

a. Can the psychologist conclude that the rate of presentation has a significant effect on memory? Test at the .05 level.

b. Use the Tukey HSD test to determine which rates of presentation are statistically different and which are not.

In: Math

Pension Plan   Job Class Plan A Plan B Plan C   Supervisor 22 26 21   Clerical 41...


Pension Plan

  Job Class

Plan A

Plan B

Plan C

  Supervisor

22

26

21

  Clerical

41

47

21

  Labor

39

63

30

  H0: Pension plan preference and job class are not related.
  H1: Pension plan preference and job class are related.
  Reject H0 if χχ2 > _____________
  χχ2 = ____________

In: Math

A radio tube inserted into a system has probability 0.2 of lasting 500 hours. 20 tubes...

A radio tube inserted into a system has probability 0.2 of lasting 500 hours. 20 tubes are tested.

1. Find probability that exactly that 'k' of these tubes will last more than 500 hours.

2. Find probability that number of tubes that last more than 500 hours will fall between 12 and 17.

3. Sketch the CDF of the random variable that describes the random phenomenon

Also: a die is rolled 120 times. Find probability that 35 or more sixes will be rolled.

Show all steps, thank you.

In: Math

Abstract 2. Mann JR and McDermott S. Are maternal genitourinary infection and pre-eclampsia associated with ADHD...

Abstract 2. Mann JR and McDermott S. Are maternal genitourinary infection and pre-eclampsia associated with ADHD in school-aged children? J Atten Disord 2011;15(8):667-73.

OBJECTIVE: To investigate the hypothesis that maternal genitourinary infection (GU) infection is associated with increased risk of ADHD. METHOD: The authors obtained linked Medicaid billing data for pregnant women and their children in South Carolina, with births from 1996 through 2002 and follow-up data through 2008. Maternal GU infections and pre-eclampsia were identified on the basis of diagnoses made during pregnancy, and cases of ADHD were identified on the basis of diagnoses made in the child's Medicaid file. RESULTS: There were 84,721 children in the data set used for analyses. Maternal genitourinary infection was associated with significantly increased odds of ADHD (OR = 1.29, 95% CI = 1.23-1.35). Pre-eclampsia was also associated with increased risk (OR = 1.19, 95% CI = 1.07-1.32). Children whose mothers had both GU infection and pre-eclampsia were 53% more likely to have ADHD, compared to those with neither exposure. When we examined specific infection diagnoses, chlamydia/nongonococcal urethritis, trichomoniasis, urinary tract infection, and candidiasis were associated with increased risk of ADHD, whereas gonorrhea was not. DISCUSSION: Maternal GU infection appeared to be associated with increased risk of ADHD, and based on the findings it was concluded that further research is needed to describe the mechanism(s) underlying the association.

The authors report “pre-eclampsia was also associated with increased risk (OR=1.19, 95% CI=1.07-1.32” of ADHD. Based only on this statement, which of the following is most likely NOT responsible for this observed result?

a

Confounding by gestational age

b

Systematic error

c

Random error

In: Math

The Lawnpoke Golf Association (LGA) has established rules that manufacturers of golf equipment must meet for...

The Lawnpoke Golf Association (LGA) has established rules that manufacturers of golf equipment must meet for their products to be acceptable for LGA events. BatOutaHell Balls uses a proprietary process to produce balls with a mean distances of 295 yards. BatOutaHell is considered that if the mean distance falls below 295 yards, the word will get out and sales will sag. Further, if the mean distance exceeds 295 yards, their balls may be rejected by LGA. Measurements of the distances are recorded in DATA. At a = 0.05, thest the no action hypothesis that the balls have a mean distance of 295 yards.

a) The test statistic of 2.238 is greater than the critical value is 2.101 therefore HO is rejected. it is reasonable to assume that the distance is not 295 yards.

b) The test statistic of 3.003 and the critical value is 2.101, therefore the test statistic is greater than the critical value of 2.101 and the null hypothesis is rejected. The distance is not 295 yards

c) The test statistic of 1.908 is less than the critical value of 2.101 therefore HO is not in the area of rejection. It is reasonto assume that the distance is about 295 yards.

d) The test statistic is 1.297 and the critical value is 2.101 therefore the test statistic is less than the critical value and the null hypothesis is not rejected. The distance is about 295 yards.

Yards
293
275
280
290
273
306
287
301
309
285
274
282
294
283
304
297
294
290
283

In: Math

Let x represent the dollar amount spent on supermarket impulse buying in a 10-minute (unplanned) shopping...

Let x represent the dollar amount spent on supermarket impulse buying in a 10-minute (unplanned) shopping interval. Based on a certain article, the mean of the xdistribution is about $26 and the estimated standard deviation is about $7.

(a) Consider a random sample of n = 60 customers, each of whom has 10 minutes of unplanned shopping time in a supermarket. From the central limit theorem, what can you say about the probability distribution of x, the average amount spent by these customers due to impulse buying? What are the mean and standard deviation of the x distribution?

-The sampling distribution of x is approximately normal with mean μx = 26 and standard error σx = $7.

The sampling distribution of x is not normal.     

-The sampling distribution of x is approximately normal with mean μx = 26 and standard error σx = $0.90.

-The sampling distribution of x is approximately normal with mean μx = 26 and standard error σx = $0.12.


Is it necessary to make any assumption about the x distribution? Explain your answer.

-It is not necessary to make any assumption about the x distribution because n is large.I

-t is necessary to assume that x has a large distribution.     

-It is not necessary to make any assumption about the x distribution because μ is large.

-It is necessary to assume that x has an approximately normal distribution.


(b) What is the probability that x is between $24 and $28? (Round your answer to four decimal places.)


(c) Let us assume that x has a distribution that is approximately normal. What is the probability that x is between $24 and $28? (Round your answer to four decimal places.)


(d) In part (b), we used x, the average amount spent, computed for 60 customers. In part (c), we used x, the amount spent by only one customer. The answers to parts (b) and (c) are very different. Why would this happen?

-The standard deviation is larger for the x distribution than it is for the x distribution.

-The standard deviation is smaller for the x distribution than it is for the x distribution.     

-The mean is larger for the x distribution than it is for the x distribution.

-The x distribution is approximately normal while the x distribution is not normal.

-The sample size is smaller for the x distribution than it is for the x distribution.


In this example, x is a much more predictable or reliable statistic than x. Consider that almost all marketing strategies and sales pitches are designed for the average customer and not the individual customer. How does the central limit theorem tell us that the average customer is much more predictable than the individual customer?

-The central limit theorem tells us that the standard deviation of the sample mean is much smaller than the population standard deviation. Thus, the average customer is more predictable than the individual customer.

-The central limit theorem tells us that small sample sizes have small standard deviations on average. Thus, the average customer is more predictable than the individual customer.    

In: Math

In Born together—Reared apart: the Landmark Minnesota twin study (2012), Nancy Segal discusses the efforts of...

In Born together—Reared apart: the Landmark Minnesota twin study (2012), Nancy Segal discusses the efforts of research psychologists at the University of Minnesota to understand similarities and differences between twins by studying sets of twins who were raised separately. The Excel Online file below contains critical reading SAT scores for several pairs of identical twins (twins who share all of their genes), one of whom was raised in a family with no other children (no siblings) and one of whom was raised in a family with other children (with siblings). Construct a spreadsheet to answer the following questions.

Open spreadsheet

a. What is the mean difference between the critical reading SAT scores for the twins raised with no siblings and the twins raised with siblings?

(to 2 decimals)

b. Provide a 90% confidence interval estimate of the mean difference between the critical reading SAT scores for the twins raised with no siblings and the twins raised with siblings.

(, ) (to 2 decimals)

c. Conduct a hypothesis test of equality of the critical reading SAT scores for the twins raised with no siblings and the twins raised with siblings.

-value is  (to 4 decimals)

At , what is your conclusion?

_________Can concludeCannot conclude that there is a difference between the mean scores for the no sibling and with sibling groups.

 
SAT Score No Siblings SAT Score With Siblings Change in SAT Score (di) Part a
415 451 After reading these instructions delete all text in this shaded area.
615 584
635 660 Use the XLMiner Analysis ToolPak to conduct your analysis.
378 437
429 457 After deleting all text in this shaded area, set the output range in
404 466 the ToolPak to the top left cell of this area (E2).
528 425
646 583 Your analysis output should fit into this shaded area.
517 486
695 652
583 484
607 650
521 468
633 574
545 465
592 673
528 523
612 650
502 509
596 649
Part b
The 90% confidence interval
C.I.Lower Limit
C.I.Upper Limit
Part c
Degrees of Freedom
Test statistic
p-value
Significance Level (Alpha) 0.01
Can we conclude that there is difference between the mean scores? (Enter "Can conclude" or "Cannot conclude")

In: Math

Cincinnati Paint Company sells quality brands of paints through hardware stores throughout the United States. The...

Cincinnati Paint Company sells quality brands of paints through hardware stores throughout the United States. The company maintains a large sales force who call on existing customers and look for new business. The national sales manager is investigating the relationship between the number of sales calls made and the miles driven by the sales representative. Also, do the sales representatives who drive the most miles and make the most calls necessarily earn the most in sales commissions? To investigate, the vice president of sales selected a sample of 25 sales representatives and determined:

  • The amount earned in commissions last month (y)
  • The number of miles driven last month (x1)
  • The number of sales calls made last month (x2)
Commissions ($000) Calls Driven Commissions ($000) Calls Driven
19 140 2,374 37 147 3,293
11 133 2,227 43 146 3,106
33 146 2,732 26 150 2,127
38 143 3,354 39 146 2,793
25 145 2,292 35 152 3,211
44 144 3,451 12 132 2,290
29 139 3,114 32 148 2,852
39 139 3,347 25 135 2,693
39 145 2,843 27 132 2,935
29 134 2,627 22 129 2,671
22 139 2,123 40 158 2,991
12 139 2,224 35 148 2,834
46 149 3,465

Develop a regression equation including an interaction term. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.)

Commissions = + Calls + Miles + x1x2

Complete the following table. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.)

Predictor Coefficient SE Coefficient t p-value
Constant
Calls
Miles
X1X2

Compute the value of the test statistic corresponding to the interaction term. (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)

Value of the test statistic

At the 0.05 significance level is there a significant interaction between the number of sales calls and the miles driven?

This is , so we conclude that there .

In: Math

Given that xx is a random variable having a Poisson distribution, compute the following: (a)  P(x=1)P(x=1) when...

Given that xx is a random variable having a Poisson distribution, compute the following:

(a)  P(x=1)P(x=1) when μ=4.5μ=4.5
P(x)=P(x)=

(b)  P(x≤8)P(x≤8)when μ=0.5μ=0.5
P(x)=P(x)=

(c)  P(x>7)P(x>7) when μ=4μ=4
P(x)=P(x)=

(d)  P(x<1)P(x<1) when μ=1μ=1
P(x)=P(x)=

In: Math

A group of college students want to have a party. They need to decide if they...

A group of college students want to have a party. They need to decide if they want to have it at the Beach (B) or at the Park (P) or in a Warehouse (W). They were ask to list in order their 1st, 2nd, and 3rd choice of where they want to have the party. Use the following table and answer the following questions. SHOW YOUR WORK to receive full credit.

10 students

8 students

13 students

1 st choice

W

B

P

2 nd choice

B

W

B

3 rd choice

P

P

W

a. How many votes were cast?

b. Use the plurality method to determine the winner.

c. Use the instant runoff method to determine the winner.

d. Use the Borda count method to determine the winner.

In: Math

We are interested in looking at ticket prices of MLB games. It is known from past...

We are interested in looking at ticket prices of MLB games. It is known from past information that the average price is $26.30, with a population standard deviation of $2.32. Suppose we take a sample of the last 5 years and find that the average ticket price is $29.94. We are interested in seeing if the average price of tickets has significantly increased. Use alpha=.10. Find the 90% confidence interval for ticket price.

a.

(28.6103, 31.2697)

b.

(28.2334, 31.6466)

c.

(27.9064, 31.9736)

d.

(27.7282, 32.1518)

We are interested in looking at ticket prices of MLB games. It is known from past information that the average price is $26.30, with a population standard deviation of $2.32. Suppose we take a sample of the last 5 years and find that the average ticket price is $29.94. We are interested in seeing if the average price of tickets has significantly increased. Use alpha=.10. The null and alternative hypotheses are:

a.

Null: The population mean is less than or equal to 26.30

Alternative: The population mean is greater than 26.30

b.

Null: The population mean is greater than or equal to 26.30

Alternative: The population mean is less than 26.30

c.

Null: The sample mean is greater than or equal to 29.94

Alternative: The sample mean is less than 29.94

d.

Null: The population mean is equal to 26.30

Alternative: The population mean does not equal 26.30

We are interested in looking at ticket prices of MLB games. It is known from past information that the average price is $26.30, with a population standard deviation of $2.32. Suppose we take a sample of the last 5 years and find that the average ticket price is $29.94. We are interested in seeing if the average price of tickets has significantly increased. Use alpha=.10. What is the critical value?

a.

z=1.2816

b.

z=-1.2816

c.

t=1.5332

d.

z=1.6449

We are interested in looking at ticket prices of MLB games. It is known from past information that the average price is $26.30, with a population standard deviation of $2.32. Suppose we take a sample of the last 5 years and find that the average ticket price is $29.94. We are interested in seeing if the average price of tickets has significantly increased. Use alpha=.10. What is the test statistic?

a.

t=3.51

b.

t=-3.51

c.

z=3.51

d.

z=-3.51

We are interested in looking at ticket prices of MLB games. It is known from past information that the average price is $26.30, with a population standard deviation of $2.32. Suppose we take a sample of the last 5 years and find that the average ticket price is $29.94. We are interested in seeing if the average price of tickets has significantly increased. Use alpha=.10. What is the p-value?

a.

0.9999

b.

0.0001

c.

0.01<p-value<0.025

d.

0.0006

In: Math