The polling organization Ipsos conducted telephone surveys in March of 2004, 2005 and 2006. In each year, 1001 people age 18 or older were asked about whether they planned to use a credit card to pay federal income taxes that year. The data are given in the accompanying table. Is there evidence that the proportion falling in the three credit card response categories is not the same for all three years? Test the relevant hypotheses using a .05 significance level. (Use 2 decimal places.)
| Intent to Pay Taxes with a Credit Card | |||
| 2004 | 2005 | 2006 | |
| Definitely/Probably Will Might/Might Not/Probably Not Definitely Not |
42 163 782 |
45 180 777 |
42 190 780 |
χ2 =
P-value interval
p < 0.0010.001 ≤ p < 0.01 0.01 ≤ p < 0.050.05 ≤ p < 0.10p ≥ 0.10
In: Math
1.Conduct an analysis and hypothesis test of your choice on the data you collected. Write a 250-500 word research summary of the findings generated in the assignments for Topics 2 through 5. The research summary should address the following.
a. Explain what type of analysis and hypothesis test was conducted on the data collected.
b. Summarize the survey results based on the results of the data you analyzed.
c. Include the Excel analysis as part of the document.
Data available below: Time stamp 1. If given the opportunity to work from home would you? Yes/No/Maybe
2. Do you consider working from home more of a employee convenience or employer benefit?
3. Who benefits more from the "Work from Home" opportunity?
| 8/11/2019 11:21:21 | Yes | Employee Convenience | Employee |
| 8/11/2019 11:22:28 | Yes | Employer Benefit | Employer |
| 8/11/2019 11:24:03 | Maybe | Employee Convenience | Employee |
| 8/11/2019 11:26:37 | Maybe | Employee Convenience | Employee |
| 8/11/2019 11:29:04 | Yes | Employee Convenience | Employee |
| 8/11/2019 11:36:23 | Yes | Employer Benefit | Employee |
| 8/11/2019 11:36:55 | Yes | Employee Convenience | Employee |
| 8/11/2019 11:43:05 | Yes | Employee Convenience | Employee |
| 8/11/2019 11:59:13 | Yes | Employer Benefit | Employee |
| 8/11/2019 12:14:33 | Maybe | Employee Convenience | Employee |
| 8/11/2019 12:22:02 | Yes | Employer Benefit | Employer |
| 8/11/2019 12:39:02 | Yes | Employee Convenience | Employee |
| 8/11/2019 12:47:51 | Yes | Employee Convenience | Employee |
| 8/11/2019 13:12:20 | Yes | Employee Convenience | Employer |
| 8/11/2019 13:49:33 | Yes | Employer Benefit | Employer |
| 8/11/2019 14:07:45 | Maybe | Employee Convenience | Employer |
| 8/11/2019 15:16:18 | Yes | Employer Benefit | Employer |
| 8/11/2019 18:55:11 | Yes | Employer Benefit | Employer |
| 8/11/2019 19:07:52 | Yes | Employer Benefit | Employer |
| 8/11/2019 20:01:33 | Maybe | Employee Convenience | Employee |
| 8/11/2019 20:03:24 | Yes | Employer Benefit | Employer |
| 8/11/2019 20:06:52 | |||
| 8/11/2019 21:38:25 | Yes | Employer Benefit | Employer |
| 8/12/2019 5:52:13 | Yes | Employer Benefit | Employer |
| 8/12/2019 6:56:04 | Yes | Employee Convenience | Employee |
| 8/12/2019 12:16:08 | Yes | Employer Benefit | Employer |
In: Math
Provide an example of where you could use correlation in real life. Explain why a t-test is necessary before you accept this correlation as being real in the population.
"Please give extreme step by step actions on how to explain this, so that I can understand to explain to class".
In: Math
What is the purpose of Reverse testing? (select all that apply)
| A.
Reverse testing will allow a read of an entire campaign response drop |
|
| B.
Reverse testing is the principle of only changing one aspect of the marketing execution at a time. |
|
|
C. When a new control execution is adopted, reverse testing allows a confirmation that the change still performs better than the previous control execution. |
|
| D.
Reverse testing protects the marketer |
In: Math
how do we interpret how typical a score is compare to the population based on the population mean and standard deviation
In: Math
You wish to test the following claim (HaHa) at a significance level of α=0.005α=0.005.
Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1<μ2Ha:μ1<μ2
You believe both populations are normally distributed, but you do not know the standard deviations for either. And you have no reason to believe the variances of the two populations are equal You obtain a sample of size n1=10n1=10 with a mean of ¯x1=70.4x¯1=70.4 and a standard deviation of s1=5.5s1=5.5 from the first population. You obtain a sample of size n2=13n2=13 with a mean of ¯x2=91x¯2=91 and a standard deviation of s2=19.1s2=19.1 from the second population.
In: Math
You wish to test the claim that the first population mean is not equal to the second population mean at a significance level of α=0.005α=0.005.
Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1≠μ2Ha:μ1≠μ2
You obtain the following two samples of data.
| Sample #1 | Sample #2 | |||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
|
In: Math
A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 77%. In a random sample of 240 married couples who completed her program, 176 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance?Perform a one-tailed test. Then fill in the table below.Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)
|
||||||||||||||||||||||||||||||||
In: Math
A scientific study on speed limits gives the following data table.
| Average speed limit | Average annual fatalities |
|---|---|
| 25 | 16 |
| 27 | 29 |
| 29 | 38 |
| 32 | 71 |
| 35 | 93 |
Using technology, it was determined that the total sum of squares (SST) was 4029.2, the sum of squares regression (SSR) was 3968.4, and the sum of squares due to error (SSE) was 60.835. Calculate R2 and determine its meaning. Round your answer to four decimal places.
Select the correct answer below:
R2=0.0153
Therefore, 1.53% of the variation in the observed y-values can be explained by the estimated regression equation.
R2=0.9849
Therefore, 98.49% of the variation in the observed y-values can be explained by the estimated regression equation.
R2=0.0151
Therefore, 1.51% of the variation in the observed y-values can be explained by the estimated regression equation.
R2=1.0153
Therefore, 10.153% of the variation in the observed y-values can be explained by the estimated regression equation.
In: Math
For each of the research studies described below, select which of the following analyses would be most appropriate. Please type your answers in the boxes exactly as they are printed here. I will check to see if Bb scored you “incorrect” for misspellings/typos, but if you type carefully (or copy-paste carefully), I can get grades done more quickly.
YOUR ANSWER CHOICES:
single sample t-test
independent samples t-test
related samples t-test
one-way independent measures ANOVA
one-way repeated measures ANOVA
Scheffe’s test
Tukey’s HSD test
two-way two-factor independent samples ANOVA
two-way mixed design ANOVA
Pearson correlation
one-way goodnesss of fit chi-square
two-way chi-square test for independence
linear regression.
The RESEARCH STUDIES:
a. Ten PSY, ten PT, and ten NSG students in a statistics course are selected at random and asked to estimate the number hours per week they are spending on the statistics course. The researcher wants to determine whether the three types of majors spend different amounts of time, on average, studying statistics. The statistical test to use would be _________________ .
b. People who are self-identified as either lower, working, middle, or upper class are compared on their attitudes toward corporal punishment of children. Attitudes are measured on a 7-point scale ranging from strongly disagree with the practice (1) to strongly agree with the practice (7). The statistical test to use would be ____________.
c. The effectiveness of a sexual harassment program is tested by taking before and after measures of sexual harassment knowledge. The knowledge scale is a 100-point scale, with higher scores indicating greater knowledge. The statistical test to use would be ___________.
d. A random sample of 100 CSS students is asked to write down their GPA and the number of hours they work per week for a salary. The researcher (the head of the Student Development Center) wants to determine whether there is a relationship between the number of hours worked and GPA. The statistical test to use would be_______________ .
e. PSY, PT, and NSG majors at CSS are asked to label the workload in their major as “light,” “average,” or “excessive.” The researcher (the chair of the Nursing Department) wants to find out if there is a greater likelihood (or frequency) of NSG majors selecting “excessive” than the other majors. The statistical test to use would be ______________.
f. A researcher wants to determine whether the average height of a sample of adult American men with Klinefleter’s syndrome (M = 5’11”) differs from the average height of adult American Men (population μ is 5’8”, σ is not known). The statistical test to use would be ______
g. A researcher wants to predict marital satisfaction scores from conflict resolution strategies, length of the marital relationship, and number of extramarital affairs. The statistical test to use would be__________ .
h. Eight MGT, eight HIM, and eight PSY students who had completed Dr. Dietrich’s statistics course were selected at random and given one of two types of statistics exam, open-book or closed-book. The researcher wants to determine whether there is an effect of major and type of exam on the mean number of correct answers. The statistical test to use would be ___________.
In: Math
A researcher is interested in whether the variation in the size of human beings is proportional throughout each part of the human. To partly answer this question they looked at the correlation between the foot length (in millimeters) and height (in centimeters) of 30 randomly selected adult males. The data is provided below. Use Excel to calculate the correlation coefficient r between the two data sets. Round your answer to two decimal places.
Foot length (mm) Height (cm)
244.9 159.2
248.5 164.8
248.1 173.7
252.3 171.7
251.6 164.6
256.5 171.4
240.3 179.7
252.7 183.1
259.7 183.2
263.3 177.9
245.7 181.6
261.0 172.9
256.6 185.2
256.0 169.6
254.7 169.0
248.1 177.6
255.9 181.9
259.4 180.4
277.6 173.0
287.7 175.0
281.2 189.6
269.0 174.1
288.4 176.1
281.8 189.7
289.1 182.7
283.2 186.0
292.5 177.8
285.4 187.7
287.5 190.5
276.8 194.1
R=
In: Math
5.A survey of 15 randomly selected employees from Bob’s factory was taken to find out how many sick days they took due to colds and flu last year. Suppose Bob didn’t take a random sample. Suppose the employees in the sample were those who responded to an advertisement Bob put out to the whole company, looking for volunteers to participate in the survey. What kind of error would be made here? THERE IS ONLY ONE CORRECT ANSWER – CHECK YOUR LECTURE NOTES.
a.Undercoverage
b.Nonresponse
c.Bias due to a self-selected sample
d.None of the above
6.A statistics student wants to know what OSU students think about parking on campus. To obtain a sample of 20 students, he knocks on the doors of residents in his dorm until he finds 20 people home who can take his survey about parking. This is a:
a.Simple random sample
b.Stratified sample
c.Convenience sample
In: Math
In: Math
Question 12 (1 point)
| X | 28 | 23 | 30 | 48 | 40 | 25 | 26 |
| Y | 91 | 106 | 112 | 192 | 155 | 130 | 101 |
The coefficient of determination for the above bivariate data is:
Question 12 options:
|
0.60 |
|
|
0.70 |
|
|
0.80 |
|
|
0.90 |
In: Math
A survey of several 9 to 11 year olds recorded the following amounts spent on a trip to the mall: $20.70, $20.82, $12.32, $19.53, $24.43
Construct the 98% confidence interval for the average amount spent by 9 to 11 year olds on a trip to the mall. Assume the population is approximately normal.
Step 1 of 4: Calculate the sample mean for the given sample data. Round your answer to two decimal places.
Step 2 of 4: Calculate the sample standard deviation for the given sample data. Round your answer to two decimal places.
Step 3 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 4 of 4: Construct the 98% confidence interval. Round your answer to two decimal places.
In: Math